How to repeat a char using printf?

Question

I\'d like to do something like printf(\"?\", count, char) to repeat a character count times.

What is the right format-string to accomplish

Answer 1

You can use the following technique:

printf("%.*s", 5, "=================");

This will print "=====" It works for me on Visual Studio, no reason it shouldn't work on all C compilers.

Answer 2

If you limit yourself to repeating either a 0 or a space you can do:

For spaces:

printf("%*s", count, "");

For zeros:

printf("%0*d", count, 0);

Answer 3

printf doesn't do that -- and printf is overkill for printing a single character.

char c = '*';
int count = 42;
for (i = 0; i < count; i ++) {
    putchar(c);
}

Don't worry about this being inefficient; putchar() buffers its output, so it won't perform a physical output operation for each character unless it needs to.

Answer 4

#include <stdio.h>
#include <string.h>

void repeat_char(unsigned int cnt, char ch) {
    char buffer[cnt + 1];
    /*assuming you want to repeat the c character 30 times*/
    memset(buffer,ch,cnd); buffer[cnt]='\0';
    printf("%s",buffer)
}

Answer 5

you can make a function that do this job and use it

#include <stdio.h>

void repeat (char input , int count )
{
    for (int i=0; i != count; i++ )
    {
        printf("%c", input);
    }
}

int main()
{
    repeat ('#', 5);
    return 0;
}

This will output

#####

Answer 6

There is no such thing. You'll have to either write a loop using printf or puts, or write a function that copies the string count times into a new string.