How to get URL parameter using jQuery or plain JavaScript?

Question

I have seen lots of jQuery examples where parameter size and name are unknown.

My URL is only going to ever have 1 string:

http://example.com?sent=ye         


        

Answer 1

This will give you a nice object to work with

    function queryParameters () {
        var result = {};

        var params = window.location.search.split(/\?|\&/);

        params.forEach( function(it) {
            if (it) {
                var param = it.split("=");
                result[param[0]] = param[1];
            }
        });

        return result;
    }

And then;

    if (queryParameters().sent === 'yes') { .....

Answer 2

So simple you can use any url and get value

function getParameterByName(name, url) {
    if (!url) url = window.location.href;
    name = name.replace(/[\[\]]/g, "\\$&");
    var regex = new RegExp("[?&]" + name + "(=([^&#]*)|&|#|$)"),
    results = regex.exec(url);
    if (!results) return null;
    if (!results[2]) return '';
    return decodeURIComponent(results[2].replace(/\+/g, " "));
}

Usage Example

// query string: ?first=value1&second=&value2
var foo = getParameterByName('first'); // "value1"
var bar = getParameterByName('second'); // "value2" 

Note: If a parameter is present several times (?first=value1&second=value2), you will get the first value (value1) and second value as (value2).

Answer 3

If you want to find a specific parameter from a specific url:

function findParam(url, param){
  var check = "" + param;
  if(url.search(check )>=0){
      return url.substring(url.search(check )).split('&')[0].split('=')[1];
  }
}  

var url = "http://www.yourdomain.com/example?id=1&order_no=114&invoice_no=254";  
alert(findParam(url,"order_no"));

Answer 4

use this

$.urlParam = function(name) {
  var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
  return results[1] || 0;
}

Answer 5

Solution from 2020

We have: http://example.com?sent=yes

let searchParams = new URLSearchParams(window.location.search)

Does sent exist?

searchParams.has('sent') // true

Is it equal to "yes"?

let param = searchParams.get('sent')

and then just compare it.

Answer 6

Using URLSearchParams:

var params = new window.URLSearchParams(window.location.search);
console.log(params.get('name'));

Be careful about the compatibility (Mostly it's fine, but IE and Edge, may be different story, check this for compatible reference: https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams)