How to get URL parameter using jQuery or plain JavaScript?

Question

I have seen lots of jQuery examples where parameter size and name are unknown.

My URL is only going to ever have 1 string:

http://example.com?sent=ye         


        

Answer 1

This one is simple and worked for me

$.urlParam = function(name){
    var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
    return results[1] || 0;
}

so if your url is http://www.yoursite.com?city=4

try this

console.log($.urlParam('city'));

Answer 2

jQuery code snippet to get the dynamic variables stored in the url as parameters and store them as JavaScript variables ready for use with your scripts:

$.urlParam = function(name){
    var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
    if (results==null) {
       return null;
    }
    return decodeURI(results[1]) || 0;
}

example.com?param1=name&param2=&id=6

$.urlParam('param1'); // name
$.urlParam('id');        // 6
$.urlParam('param2');   // null

example params with spaces

http://www.jquery4u.com?city=Gold Coast
console.log($.urlParam('city'));  
//output: Gold%20Coast



console.log(decodeURIComponent($.urlParam('city'))); 
//output: Gold Coast

Answer 3

Coffeescript version of Sameer's answer

getUrlParameter = (sParam) ->
  sPageURL = window.location.search.substring(1)
  sURLVariables = sPageURL.split('&')
  i = 0
  while i < sURLVariables.length
    sParameterName = sURLVariables[i].split('=')
    if sParameterName[0] == sParam
      return sParameterName[1]
    i++

Answer 4

What if there is & in URL parameter like filename="p&g.html"&uid=66

In this case the 1st function will not work properly. So I modified the code

function getUrlParameter(sParam) {
    var sURLVariables = window.location.search.substring(1).split('&'), sParameterName, i;

    for (i = 0; i < sURLVariables.length; i++) {
        sParameterName = sURLVariables[i].split('=');

        if (sParameterName[0] === sParam) {
            return sParameterName[1] === undefined ? true : decodeURIComponent(sParameterName[1]);
        }
    }
}

Answer 5

I always stick this as one line. Now params has the vars:

params={};location.search.replace(/[?&]+([^=&]+)=([^&]*)/gi,function(s,k,v){params[k]=v})

multi-lined:

var params={};
window.location.search
  .replace(/[?&]+([^=&]+)=([^&]*)/gi, function(str,key,value) {
    params[key] = value;
  }
);

as a function

function getSearchParams(k){
 var p={};
 location.search.replace(/[?&]+([^=&]+)=([^&]*)/gi,function(s,k,v){p[k]=v})
 return k?p[k]:p;
}

which you could use as:

getSearchParams()  //returns {key1:val1, key2:val2}

or

getSearchParams("key1")  //returns val1

Answer 6

This might be overkill, but there is a pretty popular library now available for parsing URIs, called URI.js.

Example

var uri = "http://example.org/foo.html?technology=jquery&technology=css&blog=stackoverflow";
var components = URI.parse(uri);
var query = URI.parseQuery(components['query']);
document.getElementById("result").innerHTML = "URI = " + uri;
document.getElementById("result").innerHTML += "<br>technology = " + query['technology'];

// If you look in your console, you will see that this library generates a JS array for multi-valued queries!
console.log(query['technology']);
console.log(query['blog']);

<script src="https://cdnjs.cloudflare.com/ajax/libs/URI.js/1.17.0/URI.min.js"></script>

<span id="result"></span>