Open explorer on a file

Question

In Python, how do I jump to a file in the Windows Explorer? I found a solution for jumping to folders:

import subprocess
subprocess.Popen(\'explorer \"C:\\pa         


        

Answer 1

For some reason, on windows 7 it always opens the users Path, for me following worked out:

import subprocess
subprocess.call("explorer C:\\temp\\yourpath", shell=True)

Answer 2

A nicer and safer solution (only in Windows unfortunately) is os.startfile().

When it's given a folder instead of a file, it will open Explorer.

Im aware that i do not completely answer the question since its not selecting a file, but using subprocess is always kind of a bad idea and this solution may help other people.

Answer 3

As explorer could be overridden it would be a little safer to point to the executable directly. (just had to be schooled on this too)

And while you're at it: use Python 3s current subprocess API: run()

import os
import subprocess
FILEBROWSER_PATH = os.path.join(os.getenv('WINDIR'), 'explorer.exe')

def explore(path):
    # explorer would choke on forward slashes
    path = os.path.normpath(path)

    if os.path.isdir(path):
        subprocess.run([FILEBROWSER_PATH, path])
    elif os.path.isfile(path):
        subprocess.run([FILEBROWSER_PATH, '/select,', path])

Answer 4

Alternatively, you could use the fileopenbox module of EasyGUI to open the file explorer for the user to click through and then select a file (returning the full filepath).

import easygui
file = easygui.fileopenbox()

Answer 5

From Geoff Chappell's The Windows Explorer Command Line

import subprocess
subprocess.Popen(r'explorer /select,"C:\path\of\folder\file"')