Two ways of defining functions in Scala. What is the difference?

Question

Here is a little Scala session that defines and tries out some functions:

scala> def test1(str: String) = str + str;    
test1: (str: String)java.lang.Str         


        

Answer 1

The underscore means different things in different contexts. But it can always be thought of as the thing that would go here, but doesn't need to be named.

When applied in place of parameters, the effect is to lift the method to a function.

scala> def test1(str: String) = str + str; 
test1: (str: String)java.lang.String

scala> val f1 = test1 _
f1: (String) => java.lang.String = <function1>

Note, the method has become a function of type (String) => String.

The distinction between a method and a function in Scala is that methods are akin to traditional Java methods. You can't pass them around as values. However functions are values in their own right and can be used as input parameters and return values.

The lifting can go further:

scala> val f2 = f1 _
f2: () => (String) => java.lang.String = <function0>

Lifting this function results in another function. This time of type () => (String) => (String)

From what I can tell, this syntax is equivalent to substituting all of the parameters with an underscore explicitly. For example:

scala> def add(i: Int, j: Int) = i + j
add: (i: Int,j: Int)Int

scala> val addF = add(_, _)
addF: (Int, Int) => Int = <function2>

scala> val addF2 = add _    
addF2: (Int, Int) => Int = <function2>

Answer 2

There's no difference between a def'ed function and a val'ed function:

scala> def test1 = (str: String) => str + str
test1: (String) => java.lang.String

scala> val test2 = test1
test2: (String) => java.lang.String = <function1>

scala> val test3 = (str: String) => str + str
test3: (String) => java.lang.String = <function1>

scala> val test4 = test2
test4: (String) => java.lang.String = <function1>

See? All of these are functions, which is indicated by the X => Y type they have.

scala> def test5(str: String) = str + str
test5: (str: String)java.lang.String

Do you see an X => Y type? If you do, go see an ophthalmologist, because there's none. The type here is (X)Y, commonly used to denote a method.

Actually, test1, test2, test3 and test4 are all methods, which return functions. test5 is a method which returns a java.lang.String. Also, test1 through test4 do not take parameters (only test1 could, anyway), while test5 does.

So, the difference is pretty simple. In the first case, you tried to assign a method to a val, but did not fill in the parameters the method take. So it failed, until you added a trailing underscore, which meant turn my method into a function.

In the second example you had a function, so you didn't need to do anything else.

A method is not a function, and vice versa. A function is an object of one of the FunctionN classes. A method is a handle to some piece of code associated with an object.

See various questions about methods vs functions on Stack Overflow.

Answer 3

The def declares a method within a surrounding object/class/trait, similar to the way you define methods in Java. You can only use defs within other objects/classes/traits. In the REPL, you cannot see the surrounding object because it's "hidden", but it does exist.

You cannot assign a def to a value, because the def is not a value - it's a method in the object.

The (x: T) => x * x declares and instantiates a function object, which exists at runtime. Function objects are instances of anonymous classes which extend FunctionN traits. FunctionN traits come with an apply method. The name apply is special, because it can be omitted. Expression f(x) is desugared into f.apply(x).

The bottomline is - since function objects are runtime values which exist on the heap, you can assign them to values, variables and parameters, or return them from methods as return values.

To solve the issue of assigning methods to values (which can be useful), Scala allows you to use the placeholder character to create a function object from a method. Expression test1 _ in your example above actually creates a wrapper function around the method test1 - it is equivalent to x => test1(x).