How to check task status in Celery?

Question

How does one check whether a task is running in celery (specifically, I\'m using celery-django)?

I\'ve read the documentation, and I\'ve googled, but I can\'t see a

Answer 1

I found helpful information in the

Celery Project Workers Guide inspecting-workers

For my case, I am checking to see if Celery is running.

inspect_workers = task.app.control.inspect()
if inspect_workers.registered() is None:
    state = 'FAILURE'
else:
    state = str(task.state) 

You can play with inspect to get your needs.

Answer 2

Every Task object has a .request property, which contains it AsyncRequest object. Accordingly, the following line gives the state of a Task task:

task.AsyncResult(task.request.id).state

Answer 3

Just use this API from celery FAQ

result = app.AsyncResult(task_id)

This works fine.

Answer 4

Old question but I recently ran into this problem.

If you're trying to get the task_id you can do it like this:

import celery
from celery_app import add
from celery import uuid

task_id = uuid()
result = add.apply_async((2, 2), task_id=task_id)

Now you know exactly what the task_id is and can now use it to get the AsyncResult:

# grab the AsyncResult 
result = celery.result.AsyncResult(task_id)

# print the task id
print result.task_id
09dad9cf-c9fa-4aee-933f-ff54dae39bdf

# print the AsyncResult's status
print result.status
SUCCESS

# print the result returned 
print result.result
4

Answer 5

Try:

task.AsyncResult(task.request.id).state

this will provide the Celery Task status. If Celery Task is already is under FAILURE state it will throw an Exception:

raised unexpected: KeyError('exc_type',)

Answer 6

res = method.delay()
    
print(f"id={res.id}, state={res.state}, status={res.status} ")

print(res.get())