Javascript Object push() function

Question

I have a javascript object (I actually get the data through an ajax request):

var data = {};

I have added some stuff into it:

Answer 1

push() is for arrays, not objects, so use the right data structure.

var data = [];
// ...
data[0] = { "ID": "1", "Status": "Valid" };
data[1] = { "ID": "2", "Status": "Invalid" };
// ...
var tempData = [];
for ( var index=0; index<data.length; index++ ) {
    if ( data[index].Status == "Valid" ) {
        tempData.push( data );
    }
}
data = tempData;

Answer 2

I assume that REALLY you get object from server and want to get object on output

Object.keys(data).map(k=> data[k].Status=='Invalid' && delete data[k])

var data = { 5: { "ID": "0", "Status": "Valid" } }; // some OBJECT from server response

data = { ...data,
  0: { "ID": "1", "Status": "Valid" },
  1: { "ID": "2", "Status": "Invalid" },
  2: { "ID": "3", "Status": "Valid" }
}

// solution 1: where output is sorted filtred array
let arr=Object.keys(data).filter(k=> data[k].Status!='Invalid').map(k=>data[k]).sort((a,b)=>+a.ID-b.ID);
  
// solution2: where output is filtered object
Object.keys(data).map(k=> data[k].Status=='Invalid' && delete data[k])
  
// show
console.log('Object',data);
console.log('Array ',arr);

Answer 3

You must make var tempData = new Array();

Push is an Array function.

Answer 4

    tempData.push( data[index] );

I agree with the correct answer above, but.... your still not giving the index value for the data that you want to add to tempData. Without the [index] value the whole array will be added.

Answer 5

Objects does not support push property, but you can save it as well using the index as key,

var tempData = {};
for ( var index in data ) {
  if ( data[index].Status == "Valid" ) { 
    tempData[index] = data; 
  } 
 }
data = tempData;

I think this is easier if remove the object if its status is invalid, by doing.

for(var index in data){
  if(data[index].Status == "Invalid"){ 
    delete data[index]; 
  } 
}

And finally you don't need to create a var temp –

Answer 6

Do :

var data = new Array();
var tempData = new Array();