JavaScript equivalent of jQuery's extend method

Question

Background

I have a function that takes a config object as an argument. Within the function, I also have default object. Each of those

Answer 1

To get the result in your code, you would do:

function extend(a, b){
    for(var key in b)
        if(b.hasOwnProperty(key))
            a[key] = b[key];
    return a;
}

Keep in mind that the way you used extend there will modify the default object. If you don't want that, use

$.extend({}, default, config)

A more robust solution that mimics jQuery's functionality would be as follows:

function extend(){
    for(var i=1; i<arguments.length; i++)
        for(var key in arguments[i])
            if(arguments[i].hasOwnProperty(key))
                arguments[0][key] = arguments[i][key];
    return arguments[0];
}

Answer 2

It helps me a lot when I develop with pure javascript.

function extends(defaults, selfConfig){
     selfConfig = JSON.parse(JSON.stringify(defaults));
     for (var item in config) {
         if (config.hasOwnProperty(item)) {
             selfConfig[item] = config[item];
         }
     }
     return selfConfig;
}