Get user location by IP address

Question

I have an ASP.NET website written in C#.

On this site I need to automatically show a start page based on the user\'s location.

Can I get name of user\'s city

Answer 1

It's good sample for you:

public class IpProperties
    {
        public string Status { get; set; }
        public string Country { get; set; }
        public string CountryCode { get; set; }
        public string Region { get; set; }
        public string RegionName { get; set; }
        public string City { get; set; }
        public string Zip { get; set; }
        public string Lat { get; set; }
        public string Lon { get; set; }
        public string TimeZone { get; set; }
        public string ISP { get; set; }
        public string ORG { get; set; }
        public string AS { get; set; }
        public string Query { get; set; }
    }
 public string IPRequestHelper(string url)
    {
        HttpWebRequest objRequest = (HttpWebRequest)WebRequest.Create(url);
        HttpWebResponse objResponse = (HttpWebResponse)objRequest.GetResponse();

        StreamReader responseStream = new StreamReader(objResponse.GetResponseStream());
        string responseRead = responseStream.ReadToEnd();

        responseStream.Close();
        responseStream.Dispose();

        return responseRead;
    }

    public IpProperties GetCountryByIP(string ipAddress)
    {
        string ipResponse = IPRequestHelper("http://ip-api.com/xml/" + ipAddress);
        using (TextReader sr = new StringReader(ipResponse))
        {
            using (System.Data.DataSet dataBase = new System.Data.DataSet())
            {
                IpProperties ipProperties = new IpProperties();
                dataBase.ReadXml(sr);
                ipProperties.Status = dataBase.Tables[0].Rows[0][0].ToString();
                ipProperties.Country = dataBase.Tables[0].Rows[0][1].ToString();
                ipProperties.CountryCode = dataBase.Tables[0].Rows[0][2].ToString();
                ipProperties.Region = dataBase.Tables[0].Rows[0][3].ToString();
                ipProperties.RegionName = dataBase.Tables[0].Rows[0][4].ToString();
                ipProperties.City = dataBase.Tables[0].Rows[0][5].ToString();
                ipProperties.Zip = dataBase.Tables[0].Rows[0][6].ToString();
                ipProperties.Lat = dataBase.Tables[0].Rows[0][7].ToString();
                ipProperties.Lon = dataBase.Tables[0].Rows[0][8].ToString();
                ipProperties.TimeZone = dataBase.Tables[0].Rows[0][9].ToString();
                ipProperties.ISP = dataBase.Tables[0].Rows[0][10].ToString();
                ipProperties.ORG = dataBase.Tables[0].Rows[0][11].ToString();
                ipProperties.AS = dataBase.Tables[0].Rows[0][12].ToString();
                ipProperties.Query = dataBase.Tables[0].Rows[0][13].ToString();

                return ipProperties;
            }
        }
    }

And test:

var ipResponse = GetCountryByIP("your ip address or domain name :)");

Answer 2

    public static string GetLocationIPAPI(string ipaddress)
    {
        try
        {
            IPDataIPAPI ipInfo = new IPDataIPAPI();
            string strResponse = new WebClient().DownloadString("http://ip-api.com/json/" + ipaddress);
            if (strResponse == null || strResponse == "") return "";
            ipInfo = JsonConvert.DeserializeObject<IPDataIPAPI>(strResponse);
            if (ipInfo == null || ipInfo.status.ToLower().Trim() == "fail") return "";
            else return ipInfo.city + "; " + ipInfo.regionName + "; " + ipInfo.country + "; " + ipInfo.countryCode;
        }
        catch (Exception)
        {
            return "";
        }
    }

public class IPDataIPINFO
{
    public string ip { get; set; }
    public string city { get; set; }
    public string region { get; set; }
    public string country { get; set; }
    public string loc { get; set; }
    public string postal { get; set; }
    public int org { get; set; }

}

==========================

    public static string GetLocationIPINFO(string ipaddress)
    {            
        try
        {
            IPDataIPINFO ipInfo = new IPDataIPINFO();
            string strResponse = new WebClient().DownloadString("http://ipinfo.io/" + ipaddress);
            if (strResponse == null || strResponse == "") return "";
            ipInfo = JsonConvert.DeserializeObject<IPDataIPINFO>(strResponse);
            if (ipInfo == null || ipInfo.ip == null || ipInfo.ip == "") return "";
            else return ipInfo.city + "; " + ipInfo.region + "; " + ipInfo.country + "; " + ipInfo.postal;
        }
        catch (Exception)
        {
            return "";
        }
    }

public class IPDataIPAPI
{
    public string status { get; set; }
    public string country { get; set; }
    public string countryCode { get; set; }
    public string region { get; set; }
    public string regionName { get; set; }
    public string city { get; set; }
    public string zip { get; set; }
    public string lat { get; set; }
    public string lon { get; set; }
    public string timezone { get; set; }
    public string isp { get; set; }
    public string org { get; set; }
    public string @as { get; set; }
    public string query { get; set; }
}

==============================

    private static string GetLocationIPSTACK(string ipaddress)
    {
        try
        {
            IPDataIPSTACK ipInfo = new IPDataIPSTACK();
            string strResponse = new WebClient().DownloadString("http://api.ipstack.com/" + ipaddress + "?access_key=XX384X1XX028XX1X66XXX4X04XXXX98X");
            if (strResponse == null || strResponse == "") return "";
            ipInfo = JsonConvert.DeserializeObject<IPDataIPSTACK>(strResponse);
            if (ipInfo == null || ipInfo.ip == null || ipInfo.ip == "") return "";
            else return ipInfo.city + "; " + ipInfo.region_name + "; " + ipInfo.country_name + "; " + ipInfo.zip;
        }
        catch (Exception)
        {
            return "";
        }
    }

public class IPDataIPSTACK
{
    public string ip { get; set; }
    public int city { get; set; }
    public string region_code { get; set; }
    public string region_name { get; set; }
    public string country_code { get; set; }
    public string country_name { get; set; }
    public string zip { get; set; }


}

Answer 3

Use http://ipinfo.io , You need to pay them if you make more than 1000 requests per day.

The code below requires the Json.NET package.

public static string GetUserCountryByIp(string ip)
{
    IpInfo ipInfo = new IpInfo();
    try
    {
        string info = new WebClient().DownloadString("http://ipinfo.io/" + ip);
        ipInfo = JsonConvert.DeserializeObject<IpInfo>(info);
        RegionInfo myRI1 = new RegionInfo(ipInfo.Country);
        ipInfo.Country = myRI1.EnglishName;
    }
    catch (Exception)
    {
        ipInfo.Country = null;
    }
    
    return ipInfo.Country;
}

And the IpInfo Class I used:

public class IpInfo
{
    [JsonProperty("ip")]
    public string Ip { get; set; }

    [JsonProperty("hostname")]
    public string Hostname { get; set; }

    [JsonProperty("city")]
    public string City { get; set; }

    [JsonProperty("region")]
    public string Region { get; set; }

    [JsonProperty("country")]
    public string Country { get; set; }

    [JsonProperty("loc")]
    public string Loc { get; set; }

    [JsonProperty("org")]
    public string Org { get; set; }

    [JsonProperty("postal")]
    public string Postal { get; set; }
}

Answer 4

I have tried using http://ipinfo.io and this JSON API works perfectly. First, you need to add the below mentioned namespaces:

using System.Linq;
using System.Web; 
using System.Web.UI.WebControls;
using System.Net;
using System.IO;
using System.Xml;
using System.Collections.Specialized;

For localhost it will give dummy data as AU. You can try hardcoding your IP and get results:

namespace WebApplication4
{
    public partial class WebForm1 : System.Web.UI.Page
    {

        protected void Page_Load(object sender, EventArgs e)
         {

          string VisitorsIPAddr = string.Empty;
          //Users IP Address.                
          if (HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"] != null)
          {
              //To get the IP address of the machine and not the proxy
              VisitorsIPAddr =   HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"].ToString();
          }
          else if (HttpContext.Current.Request.UserHostAddress.Length != 0)
          {
              VisitorsIPAddr = HttpContext.Current.Request.UserHostAddress;`enter code here`
          }

          string res = "http://ipinfo.io/" + VisitorsIPAddr + "/city";
          string ipResponse = IPRequestHelper(res);

        }

        public string IPRequestHelper(string url)
        {

            string checkURL = url;
            HttpWebRequest objRequest = (HttpWebRequest)WebRequest.Create(url);
            HttpWebResponse objResponse = (HttpWebResponse)objRequest.GetResponse();
            StreamReader responseStream = new StreamReader(objResponse.GetResponseStream());
            string responseRead = responseStream.ReadToEnd();
            responseRead = responseRead.Replace("\n", String.Empty);
            responseStream.Close();
            responseStream.Dispose();
            return responseRead;
        }


    }
}

Answer 5

An Alternative to using an API is to use HTML 5 location Navigator to query the browser about the User location. I was looking for a similar approach as in the subject question but I found that HTML 5 Navigator works better and cheaper for my situation. Please consider that your scinario might be different. To get the User position using Html5 is very easy:

function getLocation()
{
    if (navigator.geolocation)
    {
        navigator.geolocation.getCurrentPosition(showPosition);
    }
    else
    {
        console.log("Geolocation is not supported by this browser.");
     }
}

function showPosition(position)
{
      console.log("Latitude: " + position.coords.latitude + 
  "<br>Longitude: " + position.coords.longitude); 
}

Try it yourself on W3Schools Geolocation Tutorial

Answer 6

You'll probably have to use an external API, most of which cost money.

I did find this though, seems to be free: http://hostip.info/use.html