filename and line number of python script

Question

How can I get the file name and line number in python script.

Exactly the file information we get from an exception traceback. In this case without raising an excep

Answer 1

import inspect    

file_name = __FILE__
current_line_no = inspect.stack()[0][2]
current_function_name = inspect.stack()[0][3]

#Try printing inspect.stack() you can see current stack and pick whatever you want 

Answer 2

Thanks to mcandre, the answer is:

#python3
from inspect import currentframe, getframeinfo

frameinfo = getframeinfo(currentframe())

print(frameinfo.filename, frameinfo.lineno)

Answer 3

Whether you use currentframe().f_back depends on whether you are using a function or not.

Calling inspect directly:

from inspect import currentframe, getframeinfo

cf = currentframe()
filename = getframeinfo(cf).filename

print "This is line 5, python says line ", cf.f_lineno 
print "The filename is ", filename

Calling a function that does it for you:

from inspect import currentframe

def get_linenumber():
    cf = currentframe()
    return cf.f_back.f_lineno

print "This is line 7, python says line ", get_linenumber()