filename and line number of python script

Question

How can I get the file name and line number in python script.

Exactly the file information we get from an exception traceback. In this case without raising an excep

Answer 1

Better to use sys also-

print dir(sys._getframe())
print dir(sys._getframe().f_lineno)
print sys._getframe().f_lineno

The output is:

['__class__', '__delattr__', '__doc__', '__format__', '__getattribute__', '__hash__', '__init__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__', 'f_back', 'f_builtins', 'f_code', 'f_exc_traceback', 'f_exc_type', 'f_exc_value', 'f_globals', 'f_lasti', 'f_lineno', 'f_locals', 'f_restricted', 'f_trace']
['__abs__', '__add__', '__and__', '__class__', '__cmp__', '__coerce__', '__delattr__', '__div__', '__divmod__', '__doc__', '__float__', '__floordiv__', '__format__', '__getattribute__', '__getnewargs__', '__hash__', '__hex__', '__index__', '__init__', '__int__', '__invert__', '__long__', '__lshift__', '__mod__', '__mul__', '__neg__', '__new__', '__nonzero__', '__oct__', '__or__', '__pos__', '__pow__', '__radd__', '__rand__', '__rdiv__', '__rdivmod__', '__reduce__', '__reduce_ex__', '__repr__', '__rfloordiv__', '__rlshift__', '__rmod__', '__rmul__', '__ror__', '__rpow__', '__rrshift__', '__rshift__', '__rsub__', '__rtruediv__', '__rxor__', '__setattr__', '__sizeof__', '__str__', '__sub__', '__subclasshook__', '__truediv__', '__trunc__', '__xor__', 'bit_length', 'conjugate', 'denominator', 'imag', 'numerator', 'real']
14

Answer 2

In Python 3 you can use a variation on:

def Deb(msg = None):
  print(f"Debug {sys._getframe().f_back.f_lineno}: {msg if msg is not None else ''}")

In code, you can then use:

Deb("Some useful information")
Deb()

To produce:

123: Some useful information
124:

Where the 123 and 124 are the lines that the calls are made from.

Answer 3

Filename:

__file__
# or
sys.argv[0]

Line:

inspect.currentframe().f_lineno

(not inspect.currentframe().f_back.f_lineno as mentioned above)

Answer 4

Just to contribute,

there is a linecache module in python, here is two links that can help.

linecache module documentation
linecache source code

In a sense, you can "dump" a whole file into its cache , and read it with linecache.cache data from class.

import linecache as allLines
## have in mind that fileName in linecache behaves as any other open statement, you will need a path to a file if file is not in the same directory as script
linesList = allLines.updatechache( fileName ,None)
for i,x in enumerate(lineslist): print(i,x) #prints the line number and content
#or for more info
print(line.cache)
#or you need a specific line
specLine = allLines.getline(fileName,numbOfLine)
#returns a textual line from that number of line

For additional info, for error handling, you can simply use

from sys import exc_info
try:
     raise YourError # or some other error
except Exception:
     print(exc_info() )

Answer 5

Here's what works for me to get the line number in Python 3.7.3 in VSCode 1.39.2 (dmsg is my mnemonic for debug message):

import inspect

def dmsg(text_s):
    print (str(inspect.currentframe().f_back.f_lineno) + '| ' + text_s)

To call showing a variable name_s and its value:

name_s = put_code_here
dmsg('name_s: ' + name_s)

Output looks like this:

37| name_s: value_of_variable_at_line_37

Answer 6

Handy if used in a common file - prints file name, line number and function of the caller:

import inspect
def getLineInfo():
    print(inspect.stack()[1][1],":",inspect.stack()[1][2],":",
          inspect.stack()[1][3])