This is the dictionary
cars = {\'A\':{\'speed\':70,
\'color\':2},
\'B\':{\'speed\':60,
\'color\':3}}
Using this
Here is my solution to the problem. I think it's similar in approach, but a little simpler than some of the other answers. It also allows for an arbitrary number of sub-dictionaries and seems to work for any datatype (I even tested it on a dictionary which had functions as values):
def pprint(web, level):
for k,v in web.items():
if isinstance(v, dict):
print('\t'*level, f'{k}: ')
level += 1
pprint(v, level)
level -= 1
else:
print('\t'*level, k, ": ", v)
for x in cars:
print (x)
for y in cars[x]:
print (y,':',cars[x][y])
output:
A
color : 2
speed : 70
B
color : 3
speed : 60
A more generalized solution that handles arbitrarily-deeply nested dicts and lists would be:
def dumpclean(obj):
if isinstance(obj, dict):
for k, v in obj.items():
if hasattr(v, '__iter__'):
print k
dumpclean(v)
else:
print '%s : %s' % (k, v)
elif isinstance(obj, list):
for v in obj:
if hasattr(v, '__iter__'):
dumpclean(v)
else:
print v
else:
print obj
This produces the output:
A
color : 2
speed : 70
B
color : 3
speed : 60
I ran into a similar need and developed a more robust function as an exercise for myself. I'm including it here in case it can be of value to another. In running nosetest, I also found it helpful to be able to specify the output stream in the call so that sys.stderr could be used instead.
import sys
def dump(obj, nested_level=0, output=sys.stdout):
spacing = ' '
if isinstance(obj, dict):
print >> output, '%s{' % ((nested_level) * spacing)
for k, v in obj.items():
if hasattr(v, '__iter__'):
print >> output, '%s%s:' % ((nested_level + 1) * spacing, k)
dump(v, nested_level + 1, output)
else:
print >> output, '%s%s: %s' % ((nested_level + 1) * spacing, k, v)
print >> output, '%s}' % (nested_level * spacing)
elif isinstance(obj, list):
print >> output, '%s[' % ((nested_level) * spacing)
for v in obj:
if hasattr(v, '__iter__'):
dump(v, nested_level + 1, output)
else:
print >> output, '%s%s' % ((nested_level + 1) * spacing, v)
print >> output, '%s]' % ((nested_level) * spacing)
else:
print >> output, '%s%s' % (nested_level * spacing, obj)
Using this function, the OP's output looks like this:
{
A:
{
color: 2
speed: 70
}
B:
{
color: 3
speed: 60
}
}
which I personally found to be more useful and descriptive.
Given the slightly less-trivial example of:
{"test": [{1:3}], "test2":[(1,2),(3,4)],"test3": {(1,2):['abc', 'def', 'ghi'],(4,5):'def'}}
The OP's requested solution yields this:
test
1 : 3
test3
(1, 2)
abc
def
ghi
(4, 5) : def
test2
(1, 2)
(3, 4)
whereas the 'enhanced' version yields this:
{
test:
[
{
1: 3
}
]
test3:
{
(1, 2):
[
abc
def
ghi
]
(4, 5): def
}
test2:
[
(1, 2)
(3, 4)
]
}
I hope this provides some value to the next person looking for this type of functionality.
You have a nested structure, so you need to format the nested dictionary too:
for key, car in cars.items():
print(key)
for attribute, value in car.items():
print('{} : {}'.format(attribute, value))
This prints:
A
color : 2
speed : 70
B
color : 3
speed : 60
This will work if you know the tree only has two levels:
for k1 in cars:
print(k1)
d = cars[k1]
for k2 in d
print(k2, ':', d[k2])
pprint.pprint() is a good tool for this job:
>>> import pprint
>>> cars = {'A':{'speed':70,
... 'color':2},
... 'B':{'speed':60,
... 'color':3}}
>>> pprint.pprint(cars, width=1)
{'A': {'color': 2,
'speed': 70},
'B': {'color': 3,
'speed': 60}}