What is the best way to remove all spaces from a string in SQL Server 2008?
LTRIM(RTRIM(\' a b \'))
would remove all spaces at the right and left of th
t-sql replace http://msdn.microsoft.com/en-us/library/ms186862.aspx
replace(val, ' ', '')
Try to use like this, if normal spaces are not removed by LTRM or RTRM
LTRIM(RTRIM(REPLACE(REPLACE(REPLACE(Column_data, CHAR(9), ''), CHAR(10), ''), CHAR(13), '')))
For some reason, the replace works only with one string each time. I had a string like this "Test MSP" and I want to leave only one space.
I used the approach that @Farhan did, but with some modifications:
CREATE FUNCTION ReplaceAll
(
@OriginalString varchar(8000),
@StringToRemove varchar(20),
@StringToPutInPlace varchar(20)
)
RETURNS varchar(8000)
AS
BEGIN
declare @ResultStr varchar(8000)
set @ResultStr = @OriginalString
while charindex(@StringToRemove, @ResultStr) > 0
set @ResultStr = replace(@ResultStr, @StringToRemove, @StringToPutInPlace)
return @ResultStr
END
Then I run my update like this
UPDATE tbTest SET Description = dbo.ReplaceAll(Description, ' ', ' ') WHERE ID = 14225
Then I got this result: Test MSP
Posting here if in case someone needs it as I did.
Running on: Microsoft SQL Server 2016 (SP2)
It seems that everybody keeps referring to a single REPLACE function. Or even many calls of a REPLACE function. But when you have dynamic output with an unknown number of spaces, it wont work. Anybody that deals with this issue on a regular basis knows that REPLACE will only remove a single space, NOT ALL, as it should. And LTRIM and RTRIM seem to have the same issue. Leave it to Microsoft. Here's a sample output that uses a WHILE Loop to remove ALL CHAR(32) values (space).
DECLARE @INPUT_VAL VARCHAR(8000)
DECLARE @OUTPUT_VAL VARCHAR(8000)
SET @INPUT_VAL = ' C A '
SET @OUTPUT_VAL = @INPUT_VAL
WHILE CHARINDEX(CHAR(32), @OUTPUT_VAL) > 0 BEGIN
SET @OUTPUT_VAL = REPLACE(@INPUT_VAL, CHAR(32), '')
END
PRINT 'START:' + @INPUT_VAL + ':END'
PRINT 'START:' + @OUTPUT_VAL + ':END'
Here's the output of the above code:
START: C A :END
START:CA:END
Now to take it a step further and utilize it in an UPDATE or SELECT statement, change it to a udf.
CREATE FUNCTION udf_RemoveSpaces (@INPUT_VAL VARCHAR(8000))
RETURNS VARCHAR(8000)
AS
BEGIN
DECLARE @OUTPUT_VAL VARCHAR(8000)
SET @OUTPUT_VAL = @INPUT_VAL
-- ITTERATE THROUGH STRING TO LOOK FOR THE ASCII VALUE OF SPACE (CHAR(32)) REPLACE IT WITH BLANK, NOT NULL
WHILE CHARINDEX(CHAR(32), @OUTPUT_VAL) > 0 BEGIN
SET @OUTPUT_VAL = REPLACE(@INPUT_VAL, CHAR(32), '')
END
RETURN @OUTPUT_VAL
END
Then utilize the function in a SELECT or INSERT statement:
UPDATE A
SET STATUS_REASON_CODE = WHATEVER.dbo.udf_RemoveSpaces(STATUS_REASON_CODE)
FROM WHATEVER..ACCT_INFO A
WHERE A.SOMEVALUE = @SOMEVALUE
INSERT INTO SOMETABLE
(STATUS_REASON_CODE)
SELECT WHATEVER.dbo.udf_RemoveSpaces(STATUS_REASON_CODE)
FROM WHATEVER..ACCT_INFO A
WHERE A.SOMEVALUE = @SOMEVALUE
REPLACE() function:
REPLACE(field, ' ', '')
Reference taken from this blog:
First, Create sample table and data:
CREATE TABLE tbl_RemoveExtraSpaces
(
Rno INT
,Name VARCHAR(100)
)
GO
INSERT INTO tbl_RemoveExtraSpaces VALUES (1,'I am Anvesh Patel')
INSERT INTO tbl_RemoveExtraSpaces VALUES (2,'Database Research and Development ')
INSERT INTO tbl_RemoveExtraSpaces VALUES (3,'Database Administrator ')
INSERT INTO tbl_RemoveExtraSpaces VALUES (4,'Learning BIGDATA and NOSQL ')
GO
Script to SELECT string without Extra Spaces:
SELECT
[Rno]
,[Name] AS StringWithSpace
,LTRIM(RTRIM(REPLACE(REPLACE(REPLACE([Name],CHAR(32),'()'),')(',''),'()',CHAR(32)))) AS StringWithoutSpace
FROM tbl_RemoveExtraSpaces
Result:
Rno StringWithSpace StringWithoutSpace
----------- ----------------------------------------- ---------------------------------------------
1 I am Anvesh Patel I am Anvesh Patel
2 Database Research and Development Database Research and Development
3 Database Administrator Database Administrator
4 Learning BIGDATA and NOSQL Learning BIGDATA and NOSQL