Convert a date format in PHP

Question

I am trying to convert a date from yyyy-mm-dd to dd-mm-yyyy (but not in SQL); however I don\'t know how the date function requires a timestamp, and

Answer 1

There are two ways to implement this:

1.

    $date = strtotime(date);
    $new_date = date('d-m-Y', $date);

2.

    $cls_date = new DateTime($date);
    echo $cls_date->format('d-m-Y');

Answer 2

date('m/d/Y h:i:s a',strtotime($val['EventDateTime']));

Answer 3

You can try the strftime() function. Simple example: strftime($time, '%d %m %Y');

Answer 4

In PHP any date can be converted into the required date format using different scenarios for example to change any date format into Day, Date Month Year

$newdate = date("D, d M Y", strtotime($date));

It will show date in the following very well format

Mon, 16 Nov 2020

Answer 5

If you'd like to avoid the strtotime conversion (for example, strtotime is not being able to parse your input) you can use,

$myDateTime = DateTime::createFromFormat('Y-m-d', $dateString);
$newDateString = $myDateTime->format('d-m-Y');

Or, equivalently:

$newDateString = date_format(date_create_from_format('Y-m-d', $dateString), 'd-m-Y');

You are first giving it the format $dateString is in. Then you are telling it the format you want $newDateString to be in.

Or if the source-format always is "Y-m-d" (yyyy-mm-dd), then just use DateTime:

<?php
    $source = '2012-07-31';
    $date = new DateTime($source);
    echo $date->format('d.m.Y'); // 31.07.2012
    echo $date->format('d-m-Y'); // 31-07-2012
?>

Answer 6

Use strtotime() and date():

$originalDate = "2010-03-21";
$newDate = date("d-m-Y", strtotime($originalDate));

(See the strtotime and date documentation on the PHP site.)

Note that this was a quick solution to the original question. For more extensive conversions, you should really be using the DateTime class to parse and format :-)