void DoWork(int n);
void DoWork(const int &n);
What\'s the difference?
There are three methods you can pass values in the function
Pass by value
void f(int n){
n = n + 10;
}
int main(){
int x = 3;
f(x);
cout << x << endl;
}
Output: 3. Disadvantage: When parameter x
pass through f
function then compiler creates a copy in memory in of x. So wastage of memory.
Pass by reference
void f(int& n){
n = n + 10;
}
int main(){
int x = 3;
f(x);
cout << x << endl;
}
Output: 13. It eliminate pass by value disadvantage, but if programmer do not want to change the value then use constant reference
Constant reference
void f(const int& n){
n = n + 10; // Error: assignment of read-only reference ‘n’
}
int main(){
int x = 3;
f(x);
cout << x << endl;
}
Output: Throw error at n = n + 10
because when we pass const reference parameter argument then it is read-only parameter, you cannot change value of n.