Get name of current script in Python

Question

I\'m trying to get the name of the Python script that is currently running.

I have a script called foo.py and I\'d like to do something like this in ord

Answer 1

You can do this without importing os or other libs.

If you want to get the path of current python script, use: __file__

If you want to get only the filename without .py extension, use this:

__file__.rsplit("/", 1)[1].split('.')[0]

Answer 2

My fast dirty solution:

__file__.split('/')[-1:][0]

Answer 3

os.path.abspath(__file__) will give you an absolute path (relpath() available as well).

sys.argv[-1] will give you a relative path.

Answer 4

Note that __file__ will give the file where this code resides, which can be imported and different from the main file being interpreted. To get the main file, the special __main__ module can be used:

import __main__ as main
print(main.__file__)

Note that __main__.__file__ works in Python 2.7 but not in 3.2, so use the import-as syntax as above to make it portable.

Answer 5

If you're doing an unusual import (e.g., it's an options file), try:

import inspect
print (inspect.getfile(inspect.currentframe()))

Note that this will return the absolute path to the file.

Answer 6

For modern Python versions (3.4+), Path(__file__).name should be more idiomatic. Also, Path(__file__).stem gives you the script name without the .py extension.