What are JavaScript's builtin strings?

Question

this question is difficult to summarize in a question title

UPDATE I created a JSFiddle that builds an obfuscated string out of your input

Answer 1

In chrome, the expression ([]+/-/[(!!1+[])[1>>1]+(!!1+[])[1<<1^1]+(!1+[])[1|1<<1]+(!!1+[])[1^1]]) evaluates to "function test() { [native code] }", the [1^11<<1] evaluates to 23 (bitwise operators cause the variable to be truncated to 32 bits)

Answer 2

First of all, I would like to thank Jason and all the contributors for playing with that funny snippet. I have written that piece of code just for fun in order to send it to my wife on February 14 :) Having only Chrome installed on the laptop I had no options to check how it works in Firefox and IE. Moreover, I haven't really expected that toString() representation of build-in methods might look differently in other browsers.

Now, moving to the real problem, let's precisely have a look at the code. Yes, "v" was the real "problem" here. I found no other ways of getting this letter except parsing [native code] string, which can be taken from any built-in method. Since I limited myself with having no strings and no numbers except 1 used, I needed to exploit some method that has only available characters in its name.

Available characters can be obtained from existing keywords and string representations, i.e. from the start we had NaN, null, undefined, Infinity, true, false, and "[object Object]". Some of them can be easily converted to strings, e.g. 1/!1+[] gives "Infinity".

I have analyzed different build-in methods for arrays [], objects {}, regular expressions /(?:)/, numbers 1.1, strings "1", and discovered one beautiful method of RegExp object called test(). Its name can be assembled from all available characters, e.g. "t" and "e" from true, and "s" from false. I have created a string "test" and addressed this method using square brackets notation for regex literal /-/, correctly identified in this line:

/-/[(!!1+[])[1>>1]+(!!1+[])[1<<1^1]+(!1+[])[1|1<<1]+(!!1+[])[1^1]]

As was already discussed, this piece of code is evaluated in Chrome as:

function test() { [native code] }

in Firefox as:

function test() {
    [native code]
}

and in IE as:

 function test() {     [native code] }  

^{(in the latter pay special attention to the space before function keyword)}

So, as you clearly see, my code was getting the 24th character from the presented string, which in Chrome was "v" (as was planned), but unfortunately in Firefox and IE -- "n" and "[" respectively.

In order to make the same output in all the browsers, I have used different approach than illustrated in the other answers. Now the modified version looks like that:

javascript:[[]+1/!1][1^1][1>>1]+({}+[])[1<<1^11>>1]+([]+!!-
[])[1<<1]+[/~/+{}][+!1][-~1<<1]+/\[[^1]+\]/[([]+![])[1<<1<<
1]+(/|/[(1+{})[1+11>>>1]+[[]+{}][+!1][1]+([]+1/[])[1<<1>>1]
+([1<1]+[])[1+11>>>1+1]+[[!!1]+1][+[]][1-1]+([]+!!/!/)[1|1]
+(/1/[1]+[])[!1%1]+(-{}+{})[-1+1e1-1]+(1+[!!1])[1]+([]+1+{}
)[1<<1]+[!!/!!/+[]][+[]][1&1]]+/=/)[1e1+(1<<1|1)+(([]+/-/[(
!!1+[])[1>>1]+(!!1+[])[1<<1^1]+(!1+[])[1|1<<1]+(!!1+[])[1^1
]])[1^1]==+!1)]+(!![]+{})[1|1<<1]+[1+{}+1][!1+!1][(11>>1)+1
]](([]+/-/[(!!1+[])[1>>1]+(!!1+[])[1<<1^1]+(!1+[])[1|1<<1]+
(!!1+[])[1^1]]))[1&.1][11>>>1]+([,][~1]+[])[1-~1]+[[]+{}][!
1.1%1][11111.1%11.1*111e11|!1]+(/1/+1/[1<1][1%1])[1^11]+[[]
,[]+{}][1<<1>>>1][1||1]+(/[<+>]/[1&1|1]+[1.1])[1/11.1&1.11]

However, in order to intrigue the readers I won't provide a solution for that. I honestly believe that you will easily understand how it works... and some can even surprise their beloved in cross-browser way ;)

P.S. Yet Another Obfuscator

Inspired by Jason's idea to create a universal obfuscating tool, I have written one more. You can find it at JSBin: http://jsbin.com/amecoq/2. It can obfuscate any text that contains numbers [0-9], small latin letters [a-z], and spaces. The string length is limited mostly with your RAM (at least the body of my answer was successfully obfuscated). The output is supported by Chrome, Firefox, and IE.

^{Hint: the tool uses different obfuscation approach than was presented above.}

Answer 3

This gives a v in Chrome:

Object.getOwnPropertyNames(Object)[17][3];

And this does it in Firefox:

Object.getOwnPropertyNames(Object)[9][3]

They both pull it out of Object.prototype.preventExtensions(), so you could probably find a cross-browser way to reference that method. (It's the only 17-character name in Object.Prototype for starters.)

Feel free to build a more-obfuscated version of this and take all the credit for yourself, I'm out of time ;)

Answer 4

Here's the part that generates the n/v:

([]+/-/[(!!1+[])[1>>1]+(!!1+[])[1<<1^1]+(!1+[])[1|1<<1]+(!!1+[])[1^1]])[1^11<<1]

In Firefox, ([]+/-/[(!!1+[])[1>>1]+(!!1+[])[1<<1^1]+(!1+[])[1|1<<1]+(!!1+[])[1^1]]) evaluates to

"function test() {
    [native code]
}"

while in Chrome it is

"function test() { [native code] }"

1^11<<1 equals 23. So due to Firefox's extra whitespace, this isn't quite enough to get to the 'v', and is instead 'n'.

And this is why you shouldn't rely on Function#toString behavior. ;)

EDIT: Finally I found a reasonably obfuscated cross-browser version:

[[]+1/!1][1^1][1>>1]+({}+[])[1<<1^11>>1]+([]+!!-[])[1<<1]+[/~/+{}][+!1][-~1<<1]+([]+/-/[(!!1+[])[1>>1]+(!!1+[])[1<<1^1]+(!1+[])[1|1<<1]+(!!1+[])[1^1]])[(1^11<<1)+(parseInt("010")<10?(1+1+1+1):0)]+([,][~1]+[])[1-~1]+[[]+{}][!1.1%1][11111.1%11.1*111e11|!1]+(/1/+1/[1<1][1%1])[1^11]+[[],[]+{}][1][+1]+(/<</[1]+[])[1/1.1&1]

This replaces the n/v section with:

([]+/-/[(!!1+[])[1>>1]+(!!1+[])[1<<1^1]+(!1+[])[1|1<<1]+(!!1+[])[1^1]])[(1^11<<1)+(parseInt("010")<10?(1+1+1+1):0)]

which exploits differences in parseInt (apparently Firefox parses numbers starting with 0 as octal, while Chrome doesn't) to add 4 in Firefox's case, thus getting 'v' from 'native' in both cases (I can't find another 'v' :P).
The parseInt looks a little out of place, but that's the best I can do for now.

Answer 5

This is about as close as I could get, unfortunately it violates the convention of the original obfuscation by making a call to unescape():

unescape((/%/+[])[1]+(/1/[1]+[])[1%1]+(+!1)+(+!1)+(1e1+(11*(1-~1)<<1)))

Teardown:

(/%/+[])[1]          => "%"
(/1/[1]+[])[1%1]     => "u"
(+!1)                => "0"
(+!1)                => "0"
(1e1+(11*(1-~1)<<1)) => "76"
===========================
unescape("%u0076")   => "v"

Other ideas:

1. Somehow get to unescape("\x76")
2. Somehow convert 118 without calling String.fromCharCode()
3. Get the text from an exception with the word "Invalid" in it

Updates:

I started playing code golf and have been making it shorter, replacing parts with more 1s, etc.

Answer 6

For the general use-case, if character casing isn't a big concern, I might be inclined to cheat a little.

Create function "c" which turns a number 0 .. 25 into a character.

c=function(v){for(var i in window){for(var ci in i){if(parseInt(i[ci],(10+11+11)+(1<<1)+(1<<1))==(v+10)){return i[ci]}}}};

For performance reasons, pre-cache the letters, if you want.

l=[];for(var i=0; i<(11+11)+(1<<1)+(1<<1);i++){l[i]=c(i);}

In the Chrome console, the resulting array looks like this:

> l;
["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "K", "l", "m", "n", "o", "p", "q", "r", "S", "t", "u", "v", "w", "x", "y", "Z"]

So ... your v might be l[10+10+1].

Alternatively, a general solution like this:

p=(function(){10%11}+[])[1+11+(1<<1)]; // "%"
u=(function(){club=1}+[])[1+11+(1<<1)]; // "u"
vc=p+u+(0+[])+(0+[])+((111>>1)+11+10+[]); // "%u0076"
unescape(vc);

Or, for this specific problem, maybe just:

(function(){v=1}+[])[10+(1<<1)]; // "v"