my scenario is as follows::
class Parent
{
public:
int x;
}
class Child:public Parent
{
int x; // Same name as Parent\'s \"x\".
void Func()
{
this.x = Paren
Almost got it:
this->x = Parent::x;
this
is a pointer.
It's only a brief explaination of solutions provided by Luchian Grigore and Mr. Anubis, so if you are curious 'how this works', you should read it further.
C++ provides a so-called, "scope operator" (::
), which is perfectly suited to your task.
More details are provided at this page. You can combine this operator with class name (Parent
) to access parent's x
variable.
Accessing it via the scope resolution operator will work:
x = Parent::x;
However, I would question in what circumstances you want to do this. Your example uses public inheritance which models an "is-a" relationship. So, if you have objects that meet this criteria, but have the same members with different values and/or different meanings then this "is-a" relationship is misleading. There may be some fringe circumstances where this is appropriate, but I would state that they are definitely the exceptions to the rule. Whenever you find yourself doing this, think long and hard about why.