Python - find integer closest to 0 in list [duplicate]

Answer 1

reduce(lambda x, y : x if abs(y) > abs(x) else y, your_sequence)

Answer 2

How about this:

lst = [237, 72, -18, 237, 236, 237, 60, -158, -273, -78, 492, 243]
min((abs(x), x) for x in lst)[1]

A nice and much shorter answer:

min(lst, key=abs)