values not updated after an ajax response

前端未结

关注

 2  1734

I am sending some form data via ajax to a php script in the same page. PHP must process the data and show results in the same page.

I am using this syntax for ajax:<

相关标签:

2条回答

攒了一身酷

2020-11-28 00:35

Pass the result as parameter to updatechart()

$.ajax
({
    type: "POST",
    url: "",
    data: $("form").serialize(),
    success: function(result)
    {
        updatechart(result);      
    }
});

then access the results via parameter.

function updatechart(result) {
//.......
//.......
console.log(result);
}

Hope you're trying something like this.

0 讨论(0)

一个人的身影

2020-11-28 00:36

That is expected behavior. Move your PHP processing to a different page.

$.ajax
({
    type: "POST",
    url: "anotherphppage.php",
    data: $("form").serialize(),
    success: function(result)
    {
        updatechart(result);      
    }
});

Try this and you'll see what I mean:

<html>
    <head>
        <script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>

        <script type="text/javascript">
            $(document).ready(function() {

                $('#mybutt').click(function() {
                    $.ajax({
                        type: "POST",
                        url: "",
                        data: 'myVar=Hello',
                        success: function(data) {
                            alert(data);
                        }
                    });
                });
            }); //END $(document).ready()

        </script>
    </head>
<body>

    Try this:<br />
    <input type="button" id="mybutt" value="Click Me">

</body>
</html>

0 讨论(0)