Angular - Apply style to element depending on sibling RouterLinkActive?

Question

I do not have only one menu bar on my app that I need to be painted when the user navigates, I have another components too that needs to be painted as well. Can I achieve this j

Answer 1

you can apply the RouterLinkActive directive to an ancestor of a RouterLink.

<div routerLinkActive="active-link" [routerLinkActiveOptions]="{exact: true}">
  <a routerLink="/user/jim">Jim</a>
  <a routerLink="/user/bob">Bob</a>
</div>

More details here.

Hope this helps!!

Answer 2

If you're main navigation item merely serves as a open/close mechanism for the submenu, but you still want to use the routerLinkActive mechanism built in to Angular, you can 'dupe' the parent item to thinking it's actually a routerLink. Like this:

<nav class="main-nav">
  <a routerLink="/someroute"
     routerLinkActive="active">somelink to a route</a>
  <a (click)="openSubMenu('some-sub-menu')"
     routerLinkActive="active"><span          
     routerLink="/parentlink"
      [hidden]="true">hidden</span>Some Sub Route</a>
</nav>
<nav class="sub-nav">
  <a *ngIf="activeSubMenu ==='some-sub-menu'"
     routerLinkActive="active"
     routerLink="/parentlink/youractualsubroute">Some Sub-route</a>
</nav>

The trick is in the 'hidden' < span > element with the parent link. This will make sure the parent link is also highlighted with the routerLinkActive property on the parent element.

Answer 3

with sub menu

<ul>
  <li routerLinkActive="active" [routerLinkActiveOptions]="{exact: true}">
    <a routerLink="/">home</a>
  </li>
  <li routerLinkActive="active">
    <a routerLink="/about">about</a>
  </li>
  <li routerLinkActive="active">
    <a href="javascript:void(0)" data-toggle="dropdown">service</a>
    <ul class="dropdown-menu">
      <li routerLinkActive="active" [routerLinkActiveOptions]="{exact: true}">
        <a href="/service">service list</a>
      </li>
      <li routerLinkActive="active">
        <a href="/service/details">service Details</a>
      </li>
    </ul>
  </li>
</ul>

Answer 4

You could bind the state of the routerLinkActive directive to whether or not a class is applied to an element as follows:

<a routerLink="page1" routerLinkActive="active" #rla="routerLinkActive"/>
<span [class.active-span]="rla.isActive"></span>

.active-span {
 background-color: red;
}

#rla is a template variable You can find more info about this use case of the RouterLinkActive directive in the docs

Answer 5

You can call [class.active]="router.isActive('/parentUrlFragment',false)" on Parent Selector to have active class on the parent.

On your TS file :

import { Router, ActivatedRoute } from '@angular/router';
constructor(public router: Router){}

Now you can access the isActive method of Router in your html;

So if you have a Nested Menu Like :

Product
> Category 1
> Category 2

Selecting any of the Category Link will have active class on Product selector with [class.active]="router.isActive('/product',false)"