How to get the first file with a .txt extension in a directory with nodejs?

Question

The directory all my files are in is: \'/usr/home/jordan\' and I have many files under there (in the directory itself, but one file that is named with a .txt extension.

Answer 1

var files = fs.readdirSync(homedir);
var path = require('path');

for(var i in files) {
   if(path.extname(files[i]) === ".txt") {
       //do something
   }
}

Answer 2

You can use Glob Module as well. It works fine for me!

var glob = require( 'glob' );  
var myPath= "/fileFolder/**/*.txt";

glob(myPath, function (er, files) {
    // Files is an array of filenames.
    // Do something with files.
})

Answer 3

The lazy solution:

npm install --save readdir

and then

const {read} = require('readdir');
read("/usr/home/jordan", "**/*.txt", (err, paths) =>
    console.log(paths)
);

Answer 4

You can use fs.readdir and path.extname

var fs = require('fs')
  , path = require('path');

function getFileWithExtensionName(dir, ext) {
  fs.readdir(dir, function(files){
    for (var i = 0; i < files.length; i++) {
      if (path.extname(files[i]) === '.' + ext)
        return files[i]
    }
  });
}

var homedir = "/usr/home/jordan";
var mytxtfilepath= getFileWithExtensionName(homedir, 'txt')
fs.readfile(mytxtfilepath, function(err,data) {
  console.log(data);
});

Answer 5

You can use fs.readdir to list the files and find the one that ends with .txt:

var myPath = "/usr/home/jordan";
fs.readdir(path, function(fileNames) {
    for(var i = 0; i < fileNames.length; i++) {
      var fileName = fileNames[i];
      if(path.extname(fileName) === ".txt") {
        fs.readfile(path.join(myPath,fileName), function(err,data) {
          console.log(data);
        });
        break;
      }
    }
  }
);

Note this requires path so add var path = require("path") at the top.