I\'m new to python. Still getting my feet wet. I\'m trying to do something like this:
import sys
if ((len(sys.argv) < 3 or < len(sys.argv > 3)):
Use sys.exit()
to exit from a script.
import sys
if len(sys.argv) != 3:
print """\
This script will compare two files for something
and print out matches
Usage: theScript firstfile secondfile
"""
sys.exit(0)
sys
has a function called exit
:
sys.exit(1)
is probably what you want. Using 1
tells the program calling your program that there was an error. You should probably consider writing to sys.stderr
the reason for the error.