If i try with BitConverter,it requires a byte array and i don\'t have that.I have a Int32 and i want to convert it to UInt32.
In C++ there was no problem with that.
Int32 i = 17;
UInt32 j = (UInt32)i;
EDIT: question is unclear whether you have a long or an int?
Given this function:
string test(long vLong)
{
ulong vULong = (ulong)vLong;
return string.Format("long hex: {0:X}, ulong hex: {1:X}", vLong, vULong);
}
And this usage:
string t1 = test(Int64.MinValue);
string t2 = test(Int64.MinValue + 1L);
string t3 = test(-1L);
string t4 = test(-2L);
This will be the result:
t1 == "long hex: 8000000000000000, ulong hex: 8000000000000000"
t2 == "long hex: 8000000000000001, ulong hex: 8000000000000001"
t3 == "long hex: FFFFFFFFFFFFFFFF, ulong hex: FFFFFFFFFFFFFFFF"
t4 == "long hex: FFFFFFFFFFFFFFFE, ulong hex: FFFFFFFFFFFFFFFE"
As you can see the bits are preserved completely, even for negative values.
A simple cast is all you need. Since it's possible to lose precision doing this, the conversion is explicit.
long x = 10;
ulong y = (ulong)x;
Try:
Convert.ToUInt32()
To convert a long to a ulong, simply cast it:
long a;
ulong b = (ulong)a;
C# will NOT throw an exception if it is a negative number.