What is the benefit to limiting throws allowed by a C++ function? [closed]

Answer 1

Basically, by declaring the function with throw(); you tell the compiler that you are one hundred per cent certain that the function is not going to throw any exceptions, allowing the compiler to perform some optimizations. If your function throws an exception anyway, you're in trouble, since it most likely results in undefined behavior.

Answer 2

No one explains this better than Sutter

http://www.ddj.com/architect/184401544

The short version is

1. Never write an exception specification
2. Except possibly an empty one

Answer 3

The C++ standard requires that the unexpected() function is called if a function attempts to throw an exception that is not on its exception list. A short description of this from MSDN is here: http://msdn.microsoft.com/en-us/library/awbt5tew(VS.80).aspx

Most compilers do not actually support this C++ feature.

Answer 4

void do_something() throw(); 

This is a guarantee from the implementer's side that the function will never throw an exception. That is what a client of the function can expect. However, it also means any exception generated somewhere inside the function is handled and not rethrown back to the parent of do_something(). Shame on he who re-throw-eth from within, for there is nothing that'll stop him from throwing. This is because, throwing from within a function with an empty exception-specification is equivalent to throwing an exception not mentioned in the specification and making the std::unexpected() is to be expected followed by program termination.

BTW: The generally accepted definition of strong exception guarantee is: If a public operation fails for some reason, an exception is thrown, and the object's state is left unchanged (atomic operation).