For example, I wanted to get the file Extension from the file URL using the function below:
File name:
Greatest Hits - Lenny Kravitz (Booklet 01) [2000]
When I test your code, no exception is thrown for me. Though the proper file extension "jpg" is not returned. I would not advise using MimeTypeMap
. An easy way to obtain the file extension instead is as follows:
String file = "/mnt/sdcard/mydev/Greatest Hits - Lenny Kravitz (Booklet 01) [2000].jpg";
String exten = "";
int i = file.lastIndexOf('.');
if (i > 0) {
exten = file.substring(i+1);
}
As to why MimeTypeMap.getFileExtensionFromUrl(url)
fails? It's expecting a properly formated URL String, which yours is not. You should first encode it using URLEncoder
. For example:
String url = "/mnt/sdcard/mydev/Greatest Hits - Lenny Kravitz (Booklet 01) [2000].jpg";
url = URLEncoder.encode(url, "UTF-8");
This should allow MimeTypeMap.getFileExtensionFromUrl(url)
to work properly but unfortunately it still doesn't. Why? URLEncoder
will change all spaces to a '+' sign and getFileExtensionFromUrl
considers that an invalid character. This part, IMHO, is a bug.
From my experience, most people don't use this method. In fact, I never heard of it until you posted this question. Probably because finding a file extension is fairly trivial and most people write code similar to what I posted above.
private String getMimeTypeFromPath(String path) {
String extension = path;
int lastDot = extension.lastIndexOf('.');
if (lastDot != -1) {
extension = extension.substring(lastDot + 1);
}
// Convert the URI string to lower case to ensure compatibility with MimeTypeMap (see CB-2185).
extension = extension.toLowerCase(Locale.getDefault());
if (extension.equals("3ga")) {
return "audio/3gpp";
} else if (extension.equals("js")) {
// Missing from the map :(.
return "text/javascript";
}
return MimeTypeMap.getSingleton().getMimeTypeFromExtension(extension);
}
I use this in my project and it works unless there certain characters in the file name,
I decided to not go the route of splitting the string myself.
I made a work around for the issue:
String ext = MimeTypeMap.getFileExtensionFromUrl(sanitizeFileName(Uri.encode(name)));
And i made this method to sanitize file names:
public static String sanitizeFileName(String name)
{
byte[] invalidChars = new byte[]{34, 60, 62, 124, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 58, 42, 63, 92, 47};
for(byte i : invalidChars)
{
name = name.replace((char)i,'_');
}
return name;
}
The sanitize method is useful for other things as well.