Passing undefined parameter to function - check if variable exists [duplicate]

Answer 1

typeof is an operator, not a function, and therefore has powers that a function can't have. There's no way to do what you're trying to do.

Answer 2

The problem is nothing to do with typeof. The problem is that you cant pass undefined variables to functions.

function doNothing(obj){
}
doNothing(obj);

This code too results in the error: Uncaught ReferenceError: obj is not defined
So it doesn't matter what code you write inside your function, as it won't be called. The error happens before the function call.

typeof is an operator, not a function. This is why it does not behave in the same way as functions.

Answer 3

Your function fails as soon as you try to pass an undefined object. You can't encapsulate the typeof() function. Well, you can, but it will always throw errors when passed undefined objects.