How to query MongoDB with “like”?

Question

I want to query something with SQL\'s like query:

SELECT * FROM users  WHERE name LIKE \'%m%\'

How to do I achieve the same in

Answer 1

Regex are expensive are process.

Another way is to create an index of text and then search it using $search.

Create a text Index of fields you want to make searchable:

db.collection.createIndex({name: 'text', otherField: 'text'});

Search for a string in text index:

db.collection.find({
  '$text'=>{'$search': "The string"}
})

Answer 2

In SQL, the ‘like’ query is looks like this :

select * from users where name like '%m%'

In MongoDB console, it looks like this :

db.users.find({"name": /m/})     // Not JSON formatted

db.users.find({"name": /m/}).pretty()  // JSON formatted

In addion pretty() method will in all the places where produce formatted JSON structure which is more readable.

Answer 3

Already u got the answers but to match regex with case insensitivity

You could use the following query

db.users.find ({ "name" : /m/i } ).pretty()

The i in the /m/i indicates case insensitivity and .pretty() provides a more pretty output

Answer 4

String deepakparmar, dipak, parmar

db.getCollection('yourdb').find({"name":/^dee/})

ans deepakparmar

db.getCollection('yourdb').find({"name":/d/})

ans deepakparmar, dipak

db.getCollection('yourdb').find({"name":/mar$/})

ans deepakparmar, parmar

Answer 5

There are already many answers. I am giving different types of requirements and solutions for string search with regex.

You can do with regex which contain word i.e like. Also you can use $options => i for case insensitive search

Contains string

db.collection.find({name:{'$regex' : 'string', '$options' : 'i'}})

Doesn't Contains string only with regex

db.collection.find({name:{'$regex' : '^((?!string).)*$', '$options' : 'i'}})

Exact case insensitive string

db.collection.find({name:{'$regex' : '^string$', '$options' : 'i'}})

Start with string

db.collection.find({name:{'$regex' : '^string', '$options' : 'i'}})

End with string

db.collection.find({name:{'$regex' : 'string$', '$options' : 'i'}})

Keep this as a bookmark, and a reference for any other alterations you may need.

Answer 6

Use aggregation substring search (with index!!!):

db.collection.aggregate([{
        $project : {
            fieldExists : {
                $indexOfBytes : ['$field', 'string']
            }
        }
    }, {
        $match : {
            fieldExists : {
                $gt : -1
            }
        }
    }, {
        $limit : 5
    }
]);