How to split a std::string into a range (v3) of std::string_views?

Question

I need to split a std::string at all spaces. The resulting range should however transform it\'s element to std::string_views. I\'m struggling with the

Answer 1

(One of) the problem here is that ranges::view::split returns a range of ranges, and you cannot construct a std::string_view directly from a range.

You want something like this:

auto view = s
    | ranges::view::split(' ')
    | ranges::view::transform([](auto &&rng) {
            return std::string_view(&*rng.begin(), ranges::distance(rng));
});

There might be a better/easier way to do this but:

• &*rng.begin() will give you the address of the first character of the chunk in the original string.
• ranges::distance(rng) will give you the number of characters in this chunk. Note that this is slower than ranges::size but required here because we cannot retrieve the size of rng in constant time.