How do you declare an extern “C” function pointer

Question

So I have this code:

#include \"boost_bind.h\"
#include 
#include 
#include 

double foo(double num, double (*func)(         


        

Answer 1

You can try including cmath instead, and using static_cast<double(*)(double)>(std::log) (cast necessary to resolve to the double overload).

Otherwise, you will limit your function to extern C functions. This would work like

extern "C" typedef double (*ExtCFuncPtr)(double);

double foo(double num, ExtCFuncPtr func) {
  return 65.4;
}

Another way is to make foo a functor

struct foo {
  typedef double result_type;
  template<typename FuncPtr>
  double operator()(double num, FuncPtr f) const {
    return 65.4;
  }
};

Then you can pass foo() to boost::bind, and because it's templated, it will accept any linkage. It will also work with function objects, not only with function pointers.

Answer 2

Try using a typedef:

extern "C" {
  typedef double (*CDoubleFunc)(double);
}

double foo(double num, CDoubleFunc func) {
  return 65.4;
}