PHP assignment with a default value

Question

What\'s a nicer way to do the following, that doesn\'t call f() twice?

$x = f() ? f() : \'default\';

Answer 1

In PHP 5.3, you can also do:

  $a = f() ?: 'default';

See the manual on ?: operator.

Answer 2

function f()
{
  // conditions 
  return $if_something ? $if_something : 'default';
}

$x = f();

Answer 3

This seems to work fine:

$x = f() or $x = 'default';

Answer 4

You could save it to a variable. Testcase:

function test() {
        echo 'here';
        return 1;
}

$t = test();
$x = $t ? $t : 0;
echo $x;

Answer 5

$x = ($result = foo()) ? $result : 'default';

test