Better way to disable argument-based template parameter deduction for functions?

Question

Here is what I want to do:

template  void f(DisableDeduction obj) {std::cout << obj;}
// Here DisableDeduction aliases          


        

Answer 1

You can do it by putting T in non deducible context (to the left of ::), and use std::common_type from <type_traits>.

example:

template <typename T> void f(typename std::common_type<T>::type obj) {std::cout << obj;}