How to set thread number for the parallel collections?

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粉色の甜心
粉色の甜心 2021-02-19 23:35

I can run scala\'s foreach in parallel like that:

val N = 100
(0 until N).par.foreach(i => {
   // do something
})

But how can I set thread

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  • 2021-02-19 23:38

    Every parallel collection keeps a tasksupport object which keeps a reference to thread pool implementation.

    So, you can set the parallelism level through that object by changing the reference of tasksupport object to a new thread pool according to your need. eg:

    def f(numOfThread: Int, n: Int) = {
     import scala.collection.parallel._
     val coll = (0 to n).par
     coll.tasksupport = new ForkJoinTaskSupport(new scala.concurrent.forkjoin.ForkJoinPool(numOfThreads))
      coll.foreach(i => {
       // do something
      })
    }
    
    f(2, 100)
    

    For more info on configuring parallel collections you can refer http://docs.scala-lang.org/overviews/parallel-collections/configuration.html

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  • Official Scala documentation provides a way to change the task support of a parallel collection like this:

    import scala.collection.parallel._
    val pc = mutable.ParArray(1, 2, 3)
    pc.tasksupport = new ForkJoinTaskSupport(new scala.concurrent.forkjoin.ForkJoinPool(2))
    

    Also it is mentioned that

    The execution context task support is set to each parallel collection by default, so parallel collections reuse the same fork-join pool as the future API.

    It means that you should create single pool and reuse it. This approach causes resource leak:

    def calculate(collection: Seq[Int]): Seq[Int] = {
      val parallel = collection.par
      parallel.tasksupport = new ForkJoinTaskSupport(new ForkJoinPool(5))
      parallel.map(_ * 2).seq
    } 
    

    Right way to do this would be to reuse existing pool:

    val taskSupport = new ForkJoinTaskSupport(new ForkJoinPool(5))
    
    def calculate(collection: Seq[Int]): Seq[Int] = {
      val parallel = collection.par
      parallel.tasksupport = taskSupport
      parallel.map(_ * 2).seq
    }
    
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