randomly mapping divs

后端 未结 4 1208
闹比i
闹比i 2021-02-19 21:11

I am creating a new \"whack-a-mole\" style game where the children have to hit the correct numbers in accordance to the question. So far it is going really well, I have a timer,

相关标签:
4条回答
  • 2021-02-19 21:27

    As @aug suggests, you should know where you cannot place things at draw-time, and only place them at valid positions. The easiest way to do this is to keep currently-occupied positions handy to check them against proposed locations.

    I suggest something like

    // locations of current divs; elements like {x: 10, y: 40}
    var boxes = [];
    
    // p point; b box top-left corner; w and h width and height
    function inside(p, w, h, b) {
         return (p.x >= b.x) && (p.y >= b.y) && (p.x < b.x + w) && (p.y < b.y + h);
    }
    
    // a and b box top-left corners; w and h width and height; m is margin
    function overlaps(a, b, w, h, m) {
         var corners = [a, {x:a.x+w, y:a.y}, {x:a.x, y:a.y+h}, {x:a.x+w, y:a.y+h}];
         var bWithMargins = {x:b.x-m, y:b.y-m};
         for (var i=0; i<corners.length; i++) {
             if (inside(corners[i], bWithMargins, w+2*m, h+2*m) return true;
         }
         return false;
    }
    
    // when placing a new piece
    var box;
    while (box === undefined) {
       box = createRandomPosition(); // returns something like {x: 15, y: 92}
       for (var i=0; i<boxes.length; i++) {
          if (overlaps(box, boxes[i], boxwidth, boxheight, margin)) {
             box = undefined;
             break;
          }
       }
    }
    boxes.push(box);
    

    Warning: untested code, beware the typos.

    0 讨论(0)
  • 2021-02-19 21:38

    You can approach this problem in at least two ways (these two are popped up in my head).

    1. How about to create a 2 dimensional grid segmentation based on the number of questions, the sizes of the question panel and an array holding the position of each question coordinates and then on each time frame to position randomly these panels on one of the allowed coordinates.

    Note: read this article for further information: http://eloquentjavascript.net/chapter8.html

    1. The second approach follow the same principle, but this time to check if the panel overlap the existing panel before you place it on the canvas.
    var _grids;
    var GRID_SIZE = 20 //a constant holding the panel size; 
    function createGrids() {
        _grids = new Array();
        for (var i = 0; i< stage.stageWidth / GRID_SIZE; i++) {
            _grids[i] = new Array();
            for (var j = 0; j< stage.stageHeight / GRID_SIZE; j++) {
                _grids[i][j] = new Array();
            }
        }
    }
    

    Then on a separate function to create the collision check. I've created a gist for collision check in Actionscript, but you can use the same principle in Javascript too. I've created this gist for inspirational purposes.

    0 讨论(0)
  • 2021-02-19 21:45

    Just use a random number which is based on the width of your board and then modulo with the height...

    You get a cell which is where you can put the mole.

    For the positions the x and y should never change as you have 9 spots lets say where the mole could pop up.

    x x x
    x x x 
    x x x
    

    Each cell would be sized based on % rather then pixels and would allow re sizing the screen

    1%3 = 1 (x) 3%3 = 0 (y)

    Then no overlap is possible.

    Once the mole is positioned it can be show or hidden or moved etc based on some extended logic if required.

    If want to keep things your way and you just need a quick re-position algorithm... just set the NE to the SW if the X + width >= x of the character you want to check by setting the x = y+height of the item which overlaps. You could also enforce that logic in the drawing routine by caching the last x and ensuring the random number was not < last + width of the item.

    newY = randomFromTo(minY, maxY); newX = randomFromTo(minX, maxX); if(newX > lastX + characterWidth){ /*needful*/}

    There could still however be overlap...

    If you wanted to totally eliminate it you would need to keep track of state such as where each x was and then iterate that list to find a new position or position them first and then all them to move about randomly without intersecting which would would be able to control with just padding from that point.

    Overall I think it would be easier to just keep X starting at 0 and then and then increment until you are at a X + character width > greater then the width of the board. Then just increase Y by character height and Set X = 0 or character width or some other offset.

    newX = 0; newX += characterWidth; if(newX + chracterWidth > boardWidth) newX=0; newY+= characterHeight;

    That results in no overlap and having nothing to iterate or keep track of additional to what you do now, the only downside is the pattern of the displayed characters being 'checker board style' or right next to each other (with possible random spacing in between horizontal and vertical placement e.g. you could adjust the padding randomly if you wanted too)

    It's the whole random thing in the first place that adds the complexity.

    AND I updated your fiddle to prove I eliminated the random and stopped the overlap :)

    http://jsfiddle.net/pUwKb/51/

    0 讨论(0)
  • 2021-02-19 21:50

    The basic idea you will have to implement is that when a random coordinate is chosen, theoretically you SHOULD know the boundaries of what is not permissible and your program should know not to choose those places (whether you find an algorithm or way of simply disregarding those ranges or your program constantly checks to make sure that the number chosen isn't within the boundary is up to you. the latter is easier to implement but is a bad way of going about it simply because you are entirely relying on chance).

    Let's say for example coordinate 50, 70 is selected. If the picture is 50x50 in size, the range of what is allowed would exclude not only the dimensions of the picture, but also 50px in all directions of the picture so that no overlap may occur.

    Hope this helps. If I have time, I might try to code an example but I hope this answers the conceptual aspect of the question if that is what you were having trouble with.

    Oh and btw forgot to say really great job on this program. It looks awesome :)

    0 讨论(0)
提交回复
热议问题