Character occurrences in a String Objective C

Question

How can I count the occurrence of a character in a string?

Example

String: 123-456-7890

I want to find the occurrence count of \"-\

Answer 1

You can use replaceOccurrencesOfString:withString:options:range: method of NSString

Answer 2

The current selected answer will fail if the string starts or ends with the character you are checking for.

Use this instead:

int numberOfOccurances = (int)yourString.length - (int)[yourString stringByReplacingOccurrencesOfString:@"-" withString:@""].length;

Answer 3

int num = [[[myString mutableCopy] autorelease] replaceOccurrencesOfString:@"-" withString:@"X" options:NSLiteralSearch range:NSMakeRange(0, [myString length])];

The replaceOccurrencesOfString:withString:options:range: method returns the number of replacements that were made, so we can use that to work out how many -s are in your string.

Answer 4

You can simply do it like this:

NSString *string = @"123-456-7890";
int times = [[string componentsSeparatedByString:@"-"] count]-1;

NSLog(@"Counted times: %i", times);

Output:

Counted times: 2

Answer 5

I did this for you. try this.

unichar findC;
int count = 0;
NSString *strr = @"123-456-7890";

for (int i = 0; i<strr.length; i++) {
    findC = [strr characterAtIndex:i];
    if (findC == '-'){
        count++;
    }
}

NSLog(@"%d",count);

Answer 6

This will do the work,

int numberOfOccurences = [[theString componentsSeparatedByString:@"-"] count];