How to compare two DATE values based only on date part in Oracle?

Question

I am trying to get counts for last 30 days with the following query -

SELECT date_occured, COUNT(*) FROM problem
WHERE date_occured >= (CURRENT_DATE - 30)
GRO         


        

Answer 1

I would tend to suspect that Tony is correct and that you really only want to TRUNC the right-hand side of the expression.

If you do want to TRUNC both sides of the expression and you're encountering performance issues, you probably need a function based index

CREATE INDEX idx_problem_trunc_dt_occured
    ON problem( trunc( date_occurred ) );

That would allow your original query to use the function-based index.

Answer 2

Try using SYSDATE vs CURRENT_DATE. Sysdate uses the server's local time where CURRENT_DATE returns current date/time for the server in the client's connection's local time.

Answer 3

I think you'll want to trunc in the select part too:

 SELECT TRUNC(date_occured) AS short_date_occured, COUNT(*)
 FROM problem 
 WHERE date_occured >= trunc(SYSDATE- 30) 
 GROUP BY short_date_occured;

Answer 4

Here is the index friendly approach.

you don't need to use functions on columns if you use Oracle's Native MONTHS_BETWEEN function.

It returns difference in number of months. Days are also given as difference but on the precision side that is why I preferred to use BETWEEN clause

WHERE MONTHS_BETWEEN(date_occured, CURRENT_DATE - 30) BETWEEN 0 AND 1

Answer 5

For this condition you only need to TRUNC the right-hand side:

WHERE date_occured >= TRUNC(CURRENT_DATE - 30)

Why? Because if TRUNC(date_occured) is later than TRUNC(CURRENT_DATE - 30), then any moment in time after TRUNC(date_occured) is bound to be later than TRUNC(CURRENT_DATE - 30) too.

It is obviously always true that date_occured >= TRUNC(date_occured) (think about it).

Logic says that if A >= B and B >= C then it follows that A >= C

Now substitute:

• A : date_occured
• B : TRUNC(date_occured)
• C : TRUNC(CURRENT_DATE - 30)