Can one (re)set all the values of an array in one line (after it has been initialized)?

Question

In C, I know I can make an array like this

int myarray[5] = {a,b,c,d,e};

However, imagine the array was already initialised like

Answer 1

#include<stdio.h>
#include<stdlib.h>

int *setarray(int *ar,char *str)
{
    int offset,n,i=0;
    while (sscanf(str, " %d%n", &n, &offset)==1)
    {
        ar[i]=n;
        str+=offset;
        i+=1;
    }
    return ar;
}

int main()
{
    int *sz=malloc(5*sizeof(int)),i;

    //call
    setarray(sz,"10 30");

    //output
    for(i=0;i<2;i++)
        printf("%d\n",sz[i]);

    return 0;
}

Answer 2

memcpy(myarray, (int [5]){a,b,c,d,e}, 5*sizeof(int));

Answer 3

Here is a solution that is all standards compatible (C89, C99, C++)

It has the advantage that you only worry about entering the data in one place. None of the other code needs to change - there are no magic numbers. Array is declared on the heap. The data table is declared const.

(Click here to try running it in Codepad)

#include<stdio.h>
#include<stdlib.h>

int main()
{
unsigned int i = 0;
int *myarray = 0;
static const int  MYDATA[] = {11, 22, 33, 44, 55};

  myarray = (int*)malloc(sizeof(MYDATA));
  memcpy(myarray, MYDATA, sizeof(MYDATA));

  for(i = 0; i < sizeof(MYDATA)/sizeof(*MYDATA); ++i)  
  {
    printf("%i\n", myarray[i]);
  }

  free(myarray);

  return 0;
}

Answer 4

No, C doesn't have such feature. If you are setting all array elements to the same value use memset(3).