Why is this regex allowing a caret?

前端 未结 3 1845
鱼传尺愫
鱼传尺愫 2020-11-21 05:34

http://regexr.com/3ars8

^(?=.*[0-9])(?=.*[A-z])[0-9A-z-]{17}$

Should match \"17 alphanumeric chars, hyphens allowed too, must include at le

相关标签:
3条回答
  • 2020-11-21 06:10

    You're allowing A-z (capital 'A' through lower 'z'). You don't say what regex package you're using, but it's not necessarily clear that A-Z and a-z are contiguous; there could be other characters in between. Try this instead:

    ^(?=.*[0-9])(?=.*[A-Za-z])[0-9A-Za-z-]{17}$
    

    It seems to meet your criteria for me in regexpal.

    0 讨论(0)
  • 2020-11-21 06:22

    Because your character class [A-z] matches this symbol.

    [A-z] matches [, \, ], ^, _, `, and the English letters.

    Actually, it is a common mistake. You should use [a-zA-Z] instead to only allow English letters.

    Here is a visualization from Expresso, showing what the range [A-z] actually covers:

    screenshot from Expresso showing the ASCII table, where you can see what the [A-z] range actually covers

    So, this regex (with i option) won't capture your string.

    ^(?=.*[0-9])(?=.*[a-z])[0-9a-z-]{17}$
    

    In my opinion, it is always safer to use Ignorecase option to avoid such an issue and shorten the regex.

    0 讨论(0)
  • 2020-11-21 06:24

    regex uses ASCII printable characters from the space to the tilde range.

    Whenever we use [A-z] token it matches the following table highlighted characters. If we use [ -~] token it matches starting from SPACE to tilde.

    0 讨论(0)
提交回复
热议问题