I am currently working on a project with php. Here I want to store the image into folder using move_uploaded_file
but when I use the following code :
Hello
I know the ticket was open a while ago but i have been looking for this complete code for a while and I only found pieces of it on the net but nothing that fully worked, so here it is. I hope it helps some people.
I saw your post and i had exactly the same issue using most of the information found here - main author of the code below with w3schools.
Here is how it can be done, two ways :
// the index.php file on the server
<br><br>
<?php /* includes */ require_once 'upload.php'; ?>
<!DOCTYPE html>
<html><body> Formulaire de téléchargement d'une image <br><br>
<form action="upload.php" method="POST" enctype="multipart/form-data">
Select image to upload:
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="submit" value="Upload Image" name="submit">
</form>
</body> </html>
the upload.php file, in the same dir in this case
<?php
// writing in a sublfolder called image
$target_dir = "image/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
$check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
if($check !== false) {
echo "File is an image - " . $check["mime"] . ".";
$uploadOk = 1;
} else {
echo "File is not an image.";
$uploadOk = 0;
}
}
if ($uploadOk == 0) {
echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
// give a name and direction to the image - i changed the name to test.jpg...
$uploadfile = $_SERVER['DOCUMENT_ROOT'].$target_dir.'test.jpg';
echo "<br><br>";
echo $uploadfile;
echo "<br><br>";
if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $uploadfile)) {
echo "The file ". basename( $_FILES["fileToUpload"]["name"]). " has been uploaded.";
} else {
echo "Sorry, there was an error uploading your file.";
}
}
?>
Server that sends the file (your web server) : send.php
<?php
// I uploaded a file called sample2.jpeg from on server to another
// again you can make functions out of this
$target_url = 'http://192.168.56.103/receive.php';
//This needs to be the full path to the file you want to send.
$file_name_with_full_path = realpath('./sample2.jpeg');
/* curl will accept an array here too.
* Many examples I found showed a url-encoded string instead.
* Take note that the 'key' in the array will be the key that shows up in the
* $_FILES array of the accept script
*/
//$post = array('extra_info' => '123456','file_contents'=>'@'.$file_name_with_full_path);
$post = array('file_contents' => new CurlFile($file_name_with_full_path, 'text/plain' /* MIME-Type */,'' /*directory*/));
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$target_url);
curl_setopt($ch, CURLOPT_POST,1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $post);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
$result=curl_exec ($ch);
curl_close ($ch);
echo $result;
?>
and the file on the receiving server end : receive.php
<?php
// you can chage the destination path
$uploaddir = realpath('./') . '/';
$uploadfile = $uploaddir . basename($_FILES['file_contents']['name']);
echo "<br><br>";
print_r ($uploadfile);
echo "<br><br>";
echo '<pre>';
if (move_uploaded_file($_FILES['file_contents']['tmp_name'], $uploadfile)) {
echo "File is valid, and was successfully uploaded.\n";
} else {
echo "Possible file upload attack!\n";
}
echo 'Here is some more debugging info:';
print_r($_FILES);
echo "\n<hr />\n";
print_r($_POST);
print "</pr" . "e>\n";
?>
<br><br>Sources and references to other codes :
<br>http://stackoverflow.com/questions/12667797/using-curl-to-upload-post-data-with-files
<br>http://stackoverflow.com/questions/15200632/how-to-upload-file-using-curl-with-php
<br>http://code.stephenmorley.org/php/sending-files-using-curl/
<br>http://www.w3schools.com/php/php_file_upload.asp
Thanks again to the true authors of 99% of the code, fixed with peoples comment on stackoverflow forum : derakkilgo and W3SCHOOLS.
Use this:
$uploadfile = $_SERVER['DOCUMENT_ROOT'] . '/sites/bestinfo/images/news/CodeCogsEqn.gif';