Get All Dates of Given Month and Year in SQL Server

Question

I want to get all dates by declaring month and year in SQL server.

Can anyone please share easy lines of SQL code to get it.

For example:

Answer 1

WHERE Dates LIKE '2018-12%'

In a datetime or timestamp it goes Year-Month, so this would pull everything that matches 2018 in December. You can mod this to use your variables as well.

@month = 12;
@year = 2018;
@searchQuery = @year + @month + '%';

WHERE Dates LIKE @searchQuery

Answer 2

Same approach as t-clausen, but a more compact:

Declare @year int = 2017, @month int = 11;
WITH numbers
as
(
    Select 1 as value
    UNion ALL
    Select value + 1 from numbers
    where value + 1 <= Day(EOMONTH(datefromparts(@year,@month,1)))
)
SELECT datefromparts(@year,@month,numbers.value) Datum FROM numbers

Answer 3

DECLARE @MonthNo TINYINT = 03 -- set your month
    ,@WOYEAR SMALLINT = 2018; -- set your year

IF OBJECT_ID('TEMPDB..#TMP') IS NOT NULL
    DROP TABLE #TMP

DECLARE @START_DATE DATETIME
    ,@END_DATE DATETIME
    ,@CUR_DATE DATETIME

SET @START_DATE = DATEADD(month, @MonthNo - 1, DATEADD(year, @WOYEAR - 1900, 0))
SET @END_DATE = DATEADD(day, - 1, DATEADD(month, @MonthNo, DATEADD(year, @WOYEAR - 1900, 0)))
SET @CUR_DATE = @START_DATE

CREATE TABLE #TMP (
    WEEKDAY VARCHAR(10)
    ,DATE INT
    ,MONTH VARCHAR(10)
    ,YEAR INT
    ,dates VARCHAR(25)
    )

WHILE @CUR_DATE <= @END_DATE
BEGIN
    INSERT INTO #TMP
    SELECT DATENAME(DW, @CUR_DATE)
        ,DATEPART(DAY, @CUR_DATE)
        ,DATENAME(MONTH, @CUR_DATE)
        ,DATEPART(YEAR, @CUR_DATE)
        ,REPLACE(CONVERT(VARCHAR(9), @CUR_DATE, 6), ' ', '-')

    SET @CUR_DATE = DATEADD(DD, 1, @CUR_DATE)
END

SELECT *
FROM #TMP

Answer 4

Little modification. Query given by @t-clausen.dk will give you correct result only if you ran it on first of the month. With little change this works awesome.

DECLARE @date DATE = getdate()

;WITH N(N)AS 
(SELECT 1 FROM(VALUES(1),(1),(1),(1),(1),(1))M(N)),
tally(N)AS(SELECT ROW_NUMBER()OVER(ORDER BY N.N)FROM N,N a)


SELECT top(day(EOMONTH(@date)))
 N day,
 DATEFROMPARTS(year(@date),month(@date), n) date
FROM tally

BTW nice trick t-clausen.dk. I couldn't think of more easy way

Answer 5

Here is a query:

DECLARE @ReportDate VARCHAR(20)='2019-02-10'

DECLARE @LastDay INT =DAY(EOMONTH(@ReportDate))

DECLARE @DayStart INT=01

CREATE TABLE #TEMPMonth ([MDay] VARCHAR(20))

WHILE @LastDay>=@DayStart

BEGIN
    
INSERT INTO #TEMPMonth 
    
SELECT CAST(CAST(YEAR(@ReportDate)AS VARCHAR)+'-'+CAST(MONTH(@ReportDate)AS VARCHAR)+'-'+CAST(@DayStart AS VARCHAR) AS DATE)
    SET @DayStart+=1

END

SELECT * FROM #TEMPMonth

DROP TABLE #TEMPMonth

Answer 6

Another CTE based version

DECLARE @Month INT = 2, @Year INT = 2019

;WITH MonthDays_CTE(DayNum)
AS
(
SELECT DATEFROMPARTS(@Year, @Month, 1) AS DayNum
UNION ALL
SELECT DATEADD(DAY, 1, DayNum)
  FROM MonthDays_CTE
  WHERE DayNum < EOMONTH(DATEFROMPARTS(@Year, @Month, 1))
)
SELECT *
  FROM MonthDays_CTE