How can I position the window's position on startup to the right side of the user's screen?

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I am currently creating a sidebar-like WPF application in C#. When a user starts the application, I would like the window to automatically position it\'s self to the side of the

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北恋

2021-02-19 11:36

<body>
<script>
function myfunc()
{
    w1=window.open('http://www.google.com','Google','left=0,top=0,width=250px,height=250px');
    w2=window.open('http://www.yahoomail.com','Yahoo Mail','left=1166,top=0,width=250px,height=250px');
    w3=window.open('http://www.people.com','People Magazine','left=1166,top=500,width=250px,height=250px');
    w4=window.open('http://www.time.com','Time Magazines','left=0,top=500,width=250px,height=250px');
    w5=window.open('http://www.ew.com','Entertainment Weekly','left=550,top=250,width=250px,height=250px');

}

function myclose()
{
 w1.close(); w2.close(); w3.close(); w4.close(); w5.close();
 w6=window.open('smartwindow.html',' mywindow',',');
}
</script>
    <div id="cover">
    <img src="images/abstract.jpeg" id="1" width="500px" height="400px" alt="color defined"onClick="myfunc()"/>
     <input type="button" value="click to close all windows" onClick="myclose()"/>
     </div>
</body>

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青春惊慌失措

2021-02-19 11:39

use startPosition property or location property

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谎友^

2021-02-19 11:43

in your xaml :

WindowStartupLocation="Manual"

in the constructor :

 Left = System.Windows.SystemParameters.PrimaryScreenWidth - Width
 Top=0

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有刺的猬

2021-02-19 11:45

public MainWindow()
{
    InitializeComponent();
    WindowStartupLocation = WindowStartupLocation.Manual;
    Left =  System.Windows.Forms.SystemInformation.PrimaryMonitorSize.Width - Width;
}

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逝去的感伤

2021-02-19 11:48

Description

You can use Screen from System.Windows.Forms.

So add reference to the System.Windows.Forms.dll and System.Drawing.dll. Then change the Left and Height property in the MainWindow_Loaded method.

Sample

public MainWindow()
{
    InitializeComponent();
    this.Loaded += new RoutedEventHandler(MainWindow_Loaded);
}

void MainWindow_Loaded(object sender, RoutedEventArgs e)
{
    this.Left = System.Windows.Forms.Screen.PrimaryScreen.WorkingArea.Right - this.Width;
    this.Top = 0;
    this.Height = System.Windows.Forms.Screen.PrimaryScreen.WorkingArea.Height;
}

More Information

MSDN - Screen Class

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执念已碎

2021-02-19 11:57

You can do this without referencing win forms assemblies by using SystemParameters. In the code behind for your window XAML:

MainWindow() {
    InitializeComponents();

    this.Loaded += new RoutedEventHandler(
      delegate(object sender, RoutedEventArgs args) {
        Width = 300;
        Left = SystemParameters.VirtualScreenLeft;
        Height = SystemParameters.VirtualScreenHeight;
    }
}

SystemParameters documentation

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