PHP splitting array into two arrays based on value

Question

I have a PHP array that I am trying to split into 2 different arrays. I am trying to pull out any values that contain the word \"hidden\". So one array would contain all the v

Answer 1

Maybe it's just me, but I would go for the clarity of regular expressions...

foreach($myArray as $item) {
    if (preg_match("/hidden$/i", $item)) {
        array_push($arr2, $item);
    } else {
        array_push($arr1, $item);
    }
}

Answer 2

This should do the trick:

$myArray = array('item1', 'item2hidden', 'item3', 'item4', 'item5hidden');
$secondaryArray = array();

foreach ($myArray as $key => $value) {
    if (strpos($value, "hidden") !== false) {
        $secondaryArray[] = $value;
        unset($myArray[$key]);
    }
}

It moves all the entries that contain "hidden" from the $myArray to $secondaryArray.

Note: It's case sensitive

Answer 3

You can use array_filter:

function filtreHiddens($e) {
    if (isset($e['hidden']) && $e['hidden']) return true;
    else return false;
}

function filtreNotHiddens($e) {
    if (isset($e['hidden']) && !$e['hidden']) return true;
    else return false;
}

$arrayToFiltre = array(
    array('hidden' => true, 'someKey' => 'someVal'),
    array('hidden' => false, 'someKey1' => 'someVal1'),
    array('hidden' => true, 'someKey2' => 'someVal3'),
);

$hidden = array_filter($arrayToFiltre, 'filtreHiddens');
$notHidden = array_filter($arrayToFiltre, 'filtreNotHiddens');

print_r($hidden);
print_r($notHidden);

Answer 4

You can use array_filter() function:

$myArray = array('item1', 'item2hidden', 'item3', 'item4', 'item5hidden');

$arr1 = array_filter($myArray, function($v) { return strpos($v, 'hidden') === false; });
$arr2 = array_diff($myArray, $arr1);

Demo

Answer 5

$myArray = Array('item1', 'item2hidden', 'item3', 'item4', 'item5hidden');
$arr1 = array();
$arr2 = array();    
foreach ($myArray as $item) {
    if (strpos($item, "hidden") !== false) {
        $arr1[] = $item;
    } else {
        $arr2[] = $item;
    }
}

This solution checks if 'hidden' present at current item, if no, move to $arr1 else to $arr2