Consider:
echo 50 >> 4;
Output:
3
Why does it output 3?
As documented on php.org, the >>
operator is a bitwise shift operator which shifts bits to the right:
$a >> $b - Shift the bits of $a $b steps to the right (each step means "divide by two")
50 in binary is 110010
, and the >>
operator shifts those bits over 4 places in your example code. Although this happens in a single operation, you could think of it in multiple steps like this:
00011001
00001100
00000110
00000011
Since binary 11
is equal to 3
in decimal, the code outputs 3.
>> is the binary right-shift operator.
Your statement shifts the bits in the numeric value 50 four places to the right. Because all integers are represented in two's complement, this equals 3. An easy way to remember this is that one shift to the right is the same as dividing by 2, and one shift to the left is the same as multiplying by 2.
It shifts the bits down four places.
50 in binary is 110010.
Shifted down four places is 11, which is 3.
50 in binary is 11 0010
, shift right by 4 yields 11
which is equal to 3.
See PHP documentation and Wikipedia.
Arithmetic shift right.
It's called a right shift. 'The bits of the left operand are shifted right by the number of positions of the right operand. The bit positions vacated on the left are filled with the sign bit, and bits shifted out on the right are discarded.'
Information can be found on it here: http://php.comsci.us/etymology/operator/rightshift.php