Iterate through a Namespace

后端 未结 1 538
走了就别回头了
走了就别回头了 2021-02-19 03:30

I have got a namespace looking like this :

Namespace(aTQ=None, bE=None, bEQ=None, b=None, bQ=None, c=None, c=None, cJ=None, d=None, g=None, jR=[\'xx\',

相关标签:
1条回答
  • 2021-02-19 04:19

    I'm not sure what you know in advance, (the name jR, or only that one name has a not None value) but you can try using vars() which, like __dict__ should be a dict that has the names in your namespace as its keys. So if you have the string 'jR' somewhere,

    vars()['jR'] = vars()['jR'][0]
    

    likewise, you can get the same dict using namespace.__dict__ instead of vars()

    will leave you with the first value in ['xx','015'] as the only value for jR.

    EDIT: To be clear, since vars() and __dict__ both return dicts, you can iterate through them as:

    for k in namespace.__dict__:
        if namespace.__dict__[k] is not None:
            <<do something>>
    
    0 讨论(0)
提交回复
热议问题