Python Fibonacci Generator

Question

I need to make a program that asks for the amount of Fibonacci numbers printed and then prints them like 0, 1, 1, 2... but I can\'t get it to work. My code looks the followi

Answer 1

a = 3 #raw_input

def fib_gen():
    a, b = 0, 1
    while 1:
        yield a
        a, b = b, a + b

fs = fib_gen()
next(fs)
for i in range(a):
    print (next(fs))

Answer 2

Since you are writing a generator, why not use two yields, to save doing the extra shuffle?

import itertools as it

num_iterations = int(raw_input('How many? '))
def fib():
    a,b = 0,1
    while True:
        yield a
        b = a+b
        yield b
        a = a+b

for x in it.islice(fib(), num_iterations):
    print x

.....

Answer 3

def genFibanocciSeries():

    a=0
    b=1
    for x in range(1,10):
        yield a
        a,b = b, a+b

for fib_series in genFibanocciSeries():
    print(fib_series)

Answer 4

Your a is a global name so-to-say.

a = int(raw_input('Give amount: '))

Whenever Python sees an a, it thinks you are talking about the above one. Calling it something else (elsewhere or here) should help.

Answer 5

It looks like you are using the a twice. Try changing that to a different variable name.

The following seems to be working great for me.

def fib():
    a, b = 0, 1
    while True:
        yield a
        a, b = b, a+b

f = fib()
for x in range(100):
    print(f.next())

Answer 6

i like this version:

array = [0,1]

for i in range(20):
   x = array[0]+array[1]   
   print(x)
   array[0] = array[1]
   array[1] = x