C++11 universal initialization cause unexpected initialization?

Question

In C++ 11, The new universal initialization syntax can also be used to call a normal constructor (that doesn\'t take a initializer_list parameter). While by looking it is not ba

Answer 1

The real problem is that the API changed.

If the constructor was

Foo(int size, int value);

and you used

Foo foo(10, 2);

and the API would have been changed to

Foo(int value, int size);

you would have the same problem.