PHP - If number is divisible by 3 and 5 then echo

Question

I\'m new to PHP and trying to create the following whilst minimizing the amount of code needed. PHP should show a list of 100 then display if the number is / by 3, 5 or 3 and 5.

Answer 1

Nope... you should check first if it's divisble for 15 (3x5) (or 3 and 5) and after you can do other checks:

if($number % 15 == 0)  {
    echo "BY3 AND 5";
} elseif ($number % 5 == 0) {
    echo "BY5";
} elseif ($number % 3 == 0) {
    echo "BY3";
}
 echo "</td></tr>";

?>

Because every number divisble for 15 is also divisble for 3 and 5. So your last check could never hit

Answer 2

Update the code as given below

<?php $var = range(0, 100); ?>
<table>
<?php foreach ($var as &$number)
{
echo " <tr>
<td>$number</td>
<td>";

if($number % 3 == 0 &&  $number % 5 == 0) 
{
   echo "BY3 AND 5";
} 
elseif ($number % 5 == 0) 
{
echo "BY5";
}
elseif ($number % 3 == 0) 
{
    echo "BY3";
}
echo "</td></tr>";
}
?>

Answer 3

if I'm reading your question correct then you are looking for :

if ($number % 3 == 0 && $number %5 == 0) {
        echo "BY3 AND 5";
} elseif ($number % 3 == 0)  {
    echo "BY3";
} elseif ($number % 5 == 0) {
    echo "BY5";
}

Alternative version :

echo ($number % 3 ? ($number % 5 ? "BY3 and 5" : "BY 3") : ($number % 5 ? "BY 5" : ""));