Get latest message (row) per user in Laravel

后端 未结 9 1089
逝去的感伤
逝去的感伤 2021-02-19 01:37

TL;DR: Need latest message from each sender.

In my Laravel application I have two tables:

Users:

  • id
  • name

Messages:

相关标签:
9条回答
  • 2021-02-19 01:55

    I tried some similar approach and found out you only need to orderBy created_at immediately you find all the messages of the User then you can use Laravel's Collection to group them them by sender_id. So to my understanding, the following approach should work, i.e give you the last message receive by the user from the senders :

    So assuming you have an Authenticated User as $user which in this context is the same as receiver with receiver_id in messages table, then:

    $messages = $user->messages()
        ->orderBy('created_at', 'desc')
        ->get(['sender_id', 'body', 'created_at'])
        ->groupBy('sender_id'); //this is collections method
    

    Then loop round the collection, and fetch the first:

    $result =  new \Illuminate\Database\Eloquent\Collection ();
    foreach ($messages as $message){
        $result->push($message->first()); //the first model in the collection is the latest message
    }
    

    You should end up with the result such as:

     Illuminate\Database\Eloquent\Collection {#875
         all: [
           App\Message {#872
            sender_id: "2",
            body: "hi",
            created_at: "2016-06-21 12:00:00",
          },
          App\Message {#873
            sender_id: "4",
            body: "hi",
            created_at: "2016-06-21 12:00:00",
          },
        ]
    

    PS: A note is that I can't say how efficient this might be but one thing is for sure, is the limited number of query on the db.

    Hope it helps :)

    UPDATE:

    I will break it down as I tried it. ~

    It fetches all records of messages that belongs to user into a collection (already ordered by created_at) then, using laravel's groupBy() you have a result like the example given in that doc.

    This time I didnt convert to Array. Instead, its a collection Of Collections. like collection(collection(Messages))

    Then you pick the first Model at each index. The parameters I already passed into the get() method ensures only those fields are present (i.e ->get(['sender_id', 'body', 'created_at']). This is is totally different from mysql groupBy(), as it does not return one row for each group rather, simply groups all records by the given identifier.

    ANOTHER UPDATE

    I discovered later that calling unique() method on the resulting ordered messages would actually do the job, but in this case the unique identifier would be sender_id. (ref: Laravel's unique)That is:

    $messages = $user->messages()
        ->orderBy('created_at', 'desc')
        ->get(['sender_id', 'body', 'created_at'])
        ->unique('sender_id'); //unique replaces `groupBy`
    

    The consequence is that we don't need the foreach and the groupBy we have the result here.

    One other way to avoid repeatition (of the above) if this is needed in more than one place is to use Laravel's query scope i.e in Message model we can have something as this:

    public function scopeLatestSendersMessages($query) 
    {
         return $query->orderBy('created_at', 'desc')
             ->get(['sender_id', 'body', 'created_at'])
             ->unique('sender_id');
    }
    

    Then in the controller use:

    $messages = $user->messages()->latestSendersMessages();
    

    PS: Still not sure which one is optimally better than the other.

    0 讨论(0)
  • 2021-02-19 02:03

    Taking inspiration from this post, the most efficient way to do this would be like so:

    DB::table('messages AS m1')
        ->leftjoin('messages AS m2', function($join) {
            $join->on('m1.sender_id', '=', 'm2.sender_id');
            $join->on('m1.id', '<', 'm2.id')
        })->whereNull('m2.id')
        ->select('m1.sender_id', 'm1.body', 'm1.created_at')
        ->orderBy('m1.created_at', 'm1.desc')->get();
    

    While it is not the most Laravel friendly, it is the best solution based on performance as highlighted by the post linked in this answer above

    0 讨论(0)
  • 2021-02-19 02:05

    This is the most "Eloquent way" I have found of doing this:

    In User model:

    public function messages() {
        return $this->hasMany(Message::class, 'recipient_id');
    }
    
    public function latestMessagePerSender()
    {
        return $this->messages()
            ->whereNotExists(function ($query) {
                $query->from('messages AS m2')
                    ->whereRaw('m2.sender_id = messages.sender_id')
                    ->whereRaw('m2.created_at > messages.created_at');
        });
    }
    

    Then just $user->latestMessagePerSender

    0 讨论(0)
提交回复
热议问题