发表新帖
发表新帖

Reading data from URL

前端 未结
关注
5 1674
生来不讨喜
生来不讨喜 2021-02-19 00:59

Is there a reasonably easy way to get data from some url? I tried the most obvious version, does not work:

readcsv(\"https://dl.dropboxusercontent.com/u/.../test
相关标签:
5条回答
  • 自闭症患者
    2021-02-19 01:14

    The Requests package seems to work pretty well. There are others (see the entire package list) but Requests is actively maintained.

    Obtaining it

    julia> Pkg.add("Requests")

julia> using Requests

    Using it

    You can use one of the exported functions that correspond to the various HTTP verbs get, post, etc which returns a Response type

    julia> res = get("http://julialang.org")
Response(200 OK, 21 Headers, 20913 Bytes in Body)

julia> typeof(res)
Response (constructor with 8 methods)

    And then, for example, you can print the data using @printf

    julia> @printf("%s",res.data);
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-us" lang="en-us">
<head>
  <meta http-equiv="content-type" content="text/html; charset=utf-8" />
...
    0 讨论(0)
  • 一向
    2021-02-19 01:15

    If you want to read a CSV from a URL, you can use the Requests package as @waTeim shows and then read the data through an IOBuffer. See example below.

    Or, as @Colin T Bowers comments, you could use the currently (December 2017) more actively maintained HTTP.jl package like this:

    julia> using HTTP

julia> res = HTTP.get("https://www.ferc.gov/docs-filing/eqr/q2-2013/soft-tools/sample-csv/transaction.txt");

julia> mycsv = readcsv(res.body);

julia> for (colnum, myheader) in enumerate(mycsv[1,:])
           println(colnum, '\t', myheader)
       end
1   transaction_unique_identifier
2   seller_company_name
3   customer_company_name
4   customer_duns_number
5   tariff_reference
6   contract_service_agreement
7   trans_id
8   transaction_begin_date
9   transaction_end_date
10  time_zone
11  point_of_delivery_control_area
12  specific location
13  class_name
14  term_name
15  increment_name
16  increment_peaking_name
17  product_name
18  transaction_quantity
19  price
20  units
21  total_transmission_charge
22  transaction_charge

    Using the Requests.jl package:

    julia> using Requests

julia> res = get("https://www.ferc.gov/docs-filing/eqr/q2-2013/soft-tools/sample-csv/transaction.txt");

julia> mycsv = readcsv(IOBuffer(res.data));

julia> for (colnum, myheader) in enumerate(mycsv[1,:])
         println(colnum, '\t', myheader)
       end
1   transaction_unique_identifier
2   seller_company_name
3   customer_company_name
4   customer_duns_number
5   tariff_reference
6   contract_service_agreement
7   trans_id
8   transaction_begin_date
9   transaction_end_date
10  time_zone
11  point_of_delivery_control_area
12  specific location
13  class_name
14  term_name
15  increment_name
16  increment_peaking_name
17  product_name
18  transaction_quantity
19  price
20  units
21  total_transmission_charge
22  transaction_charge
    0 讨论(0)
  • 南旧
    2021-02-19 01:23

    If it is directly a csv file, something like this should work:

    A = readdlm(download(url),';')
    0 讨论(0)
  • 隐瞒了意图╮
    2021-02-19 01:26

    Nowadays you can also use UrlDownload.jl which is pure Julia, take care of download details, process data in-memory and can also work with compressed files.

    Usage is straightforward

    using UrlDownload

A = urldownload("https://data.ok.gov/sites/default/files/unspsc%20codes_3.csv")
    0 讨论(0)
  • 面向向阳花
    2021-02-19 01:37

    If you are looking to read into a dataframe, this will also work in Julia:

    using CSV   

dataset = CSV.read(download("https://mywebsite.edu/ml/machine-learning-databases/my.data"))
    0 讨论(0)
 看不清?
提交回复
热议问题