FBSDKShareLinkContent is not setting the contentDescription and contentTitle

Question

I am trying to share a link on the Facebook using FBSDKShareLinkContent.

I have set the URL, description and title. SDK is automatically populates the titl

Answer 1

I've faced a same problem and found out one workaround - direct setting mode of FBSDKShareDialog instance to FBSDKShareDialogModeFeedWeb.

FBSDKShareDialog* dialog = [[FBSDKShareDialog alloc] init];
dialog.mode = FBSDKShareDialogModeFeedWeb;
dialog.shareContent = content;
dialog.fromViewController = self;
[dialog show];

It displays the feed dialog in a UIWebView within the app with preview of your post with right title and description.

Answer 2

Use quote property of FBSDKShareLinkContent instead

FBSDKShareLinkContent *linkContent = [FBSDKShareLinkContent new];
linkContent.quote = @"your quote";

FBSDKShareDialog *shareDialog = [FBSDKShareDialog new];
shareDialog.shareContent = linkContent;

setContentTitle and setContentDescription have been deprecated from Graph API 2.9. For more information, see https://developers.facebook.com/docs/apps/changelog#v2_9_deprecations

Answer 3

I tried this code and it works perfectly on my virtual device, until I setted up Facebook account in setting of phone. After I set that, every time that I want to open dialog was opened default iOS social share dialog. Delete your account, if it exist in settings, or just install FB application, in documentation I saw that we need FB app for sharing.

If this will not help, you can always use Social Share framework of iOS, here is the example.

http://www.appcoda.com/ios-programming-101-integrate-twitter-and-facebook-sharing-in-ios-6/

Hope this will help, by the way, today I stack on this problems too, now every thing working great with this Social Sharing framework of iOS.

Answer 4

FBSDKShareDialogMode sets to FeedBrowser resolves my issue

let dialog = FBSDKShareDialog()
dialog.fromViewController = self
dialog.shareContent = shareLink
dialog.mode = FBSDKShareDialogMode.FeedBrowser
dialog.show()